You are not logged in.
#1 2010-11-14 00:41:55
- 123ronnie321
- Full Member
Offline
Challenge
All u hv to do is find functions satisfying -
f` = g
g`= h
h`= f
f,g,h are different functions.
where f means f(x) and f` means f`(x)
-------
A simpler version -
f` = g
g`= f
f(0) = 1
g(0) = 0
find f(1)
#2 2010-11-14 10:04:00
- bobbym
- Administrator
Online
Re: Challenge
Hi 123ronnie321;
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#3 2010-11-16 02:17:57
- 123ronnie321
- Full Member
Offline
Re: Challenge
i did it this way
Last edited by 123ronnie321 (2010-11-22 03:01:15)
#4 2010-11-16 04:56:50
- bobbym
- Administrator
Online
Re: Challenge
That does not give you the analytical answer. Do you know what those series represent?
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#5 2010-11-17 18:25:56
- 123ronnie321
- Full Member
Offline
Re: Challenge
hi bobby
i tried condensing those series and i got the result very similar to what you posted. I must have made some silly error while calculating.
i wrote the series of e^x, e^wx & e^(w^2)x {where w = complex cube root of unity} and added the three......
#6 2010-11-18 00:09:24
- bobbym
- Administrator
Online
Re: Challenge
Hi;
What you probably did wrong was you forgot to divide by 3.
Where 1,w1 and w2 are the roots of unity.
Same answer as I got. But that is not how I did it.
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#7 2010-11-20 16:40:15
- sameer mishra
- Full Member
Offline
Re: Challenge
hello friend in my openion you are wrong in frist question
#8 2010-11-20 16:57:35
- bobbym
- Administrator
Online
Re: Challenge
Hi sameer mishra;
sameer mishra wrote:
hello friend in my openion you are wrong in frist question
Comments like that are kind of confusing. Can you be more specific. We both have names which will help to differentiate us from each other.
Do you mean me or 123ronnie321. Please use the usernames.
Sorry, opinions have little weight in mathematics. Just saying someone is wrong is adversarial and unproductive.
You must back up your claims. Can you prove your statement?
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.