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## #1 2005-10-12 12:22:45

M_TREY
Member
Registered: 2005-10-12
Posts: 2

### Tricky Puzzle

You have a pentagon with three circles on each side. One on each corner and one in the middle.  With a total of 10 circles. You need to put in a number 1-10 into each circle and you cant reuse any numbers. Each side needs to add up to the same sum. I read somewhere that the 4 possibilites make the sums of 14, 16, 17, 19. I solved the one for 14 but cant do the others. Any answers would be appreciated.

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## #2 2005-10-12 19:34:57

MathsIsFun
Registered: 2005-01-21
Posts: 7,659

### Re: Tricky Puzzle

Would you have an illustration of this?

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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## #3 2005-10-12 21:57:39

ganesh
Registered: 2005-06-28
Posts: 23,084

### Re: Tricky Puzzle

Let the pentagon be ABCDE
AB is 7,2,10
BC is 10,1,8
CD is 8,5,6
DE is 6,4,9 and
EA is 9,3,7

The total is 19 on all sides!

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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## #4 2005-10-13 12:16:28

M_TREY
Member
Registered: 2005-10-12
Posts: 2

### Re: Tricky Puzzle

I got that answer right before i checked the posts. haha

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