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**M_TREY****Member**- Registered: 2005-10-12
- Posts: 2

You have a pentagon with three circles on each side. One on each corner and one in the middle. With a total of 10 circles. You need to put in a number 1-10 into each circle and you cant reuse any numbers. Each side needs to add up to the same sum. I read somewhere that the 4 possibilites make the sums of 14, 16, 17, 19. I solved the one for 14 but cant do the others. Any answers would be appreciated.

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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,673

Would you have an illustration of this?

You can either link to one, or upload one (via "Post Reply")

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 23,583

Let the pentagon be ABCDE

AB is 7,2,10

BC is 10,1,8

CD is 8,5,6

DE is 6,4,9 and

EA is 9,3,7

The total is 19 on all sides!

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**M_TREY****Member**- Registered: 2005-10-12
- Posts: 2

I got that answer right before i checked the posts. haha

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