I need help with this question... someone please help?
Determine the equation of the line perpindicular to 4x-2y+7=0 and having the same y-intercept 2x+3y-10=0
It would be great if you can help me out in this question!
The slope of 4x-2y+7=0 is 2.
Therefore, the perpendicular to this line has a slope -1/2.
The y-intercept 2x+3y-10=0
Therefore, the line passes through (0, 10/3)
The equation of the line would be
y - 10/3 = -1/2(x - 0) = -x/2
2y - 20/3 = -x
x + 2y - 20/3 = 0
3x + 6y - 20 = 0 is the required equation.
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