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**Ashley****Guest**

I need help with this question... someone please help?

Determine the equation of the line perpindicular to 4x-2y+7=0 and having the same y-intercept 2x+3y-10=0

It would be great if you can help me out in this question!

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 23,064

The slope of 4x-2y+7=0 is 2.

Therefore, the perpendicular to this line has a slope -1/2.

The y-intercept 2x+3y-10=0

is 10/3.

Therefore, the line passes through (0, 10/3)

The equation of the line would be

y - 10/3 = -1/2(x - 0) = -x/2

2y - 20/3 = -x

x + 2y - 20/3 = 0

3x + 6y - 20 = 0 is the required equation.

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