Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #1 20070615 11:32:20
Introduction to DerivativesA very longwinded Introduction to Derivatives "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman #2 20070615 20:10:24
Re: Introduction to DerivativesNice pages! Very well explained, and you've got first principles in there as well. Why did the vector cross the road? It wanted to be normal. #3 20070616 00:18:02
Re: Introduction to DerivativesNice pages. No errors spotted when rushed through. Derivatives of other functions from first principles can be added, and Sinx, and other trignometric functions. Character is who you are when no one is looking. #4 20070617 14:37:00
Re: Introduction to Derivatives
I agree ... have updated. What do you think? "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman #5 20070619 13:12:11
Re: Introduction to DerivativesPretty nice!! igloo myrtilles fourmis #6 20070619 14:04:27
Re: Introduction to DerivativesYes, it is! But remember, Δx cannot be zero "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman #7 20070619 14:13:46
Re: Introduction to DerivativesAh, but MathIsFun, what if Δx was 0? Then it must be that Δf(x) is also 0, no matter what the function. So the question we are asking is "What is the slope of a single point of any function?" if we consider Δf(x)/Δx. And the answer to this, which happens to be the same as the answer to 0/0, is indeterminate. Because a function can have any slope at a single point. "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." 