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You are not logged in. #1 2007-03-13 14:44:14
Degree of an ExpressionI am still working on creating some pages on Limits, and along the way I made this page: "The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman #2 2007-03-13 18:59:12
Re: Degree of an ExpressionI am thinking of adding that you can also work out the Degree by taking the limit of log(f(x))/log(x) as x goes to infinity. "The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman #3 2007-03-13 19:04:13
Re: Degree of an Expressionits fine and i tottaly agree (top one) Zappzter - New IM app! Unsure of which room to join? "ZNU" is made to help new users. c: #4 2007-03-13 21:46:38
Re: Degree of an ExpressionNice job on that page, I never knew about the fractions thing. Well... there isn't really much to talk about regarding degree apart from what you've already said... and perhaps that limit thing... so yeah #5 2007-03-13 21:51:53
Re: Degree of an ExpressionI agree with Toast. You've pretty much said everything you can say about degree, and explained it very well. Why did the vector cross the road? It wanted to be normal. #6 2007-03-14 14:35:57
Re: Degree of an ExpressionThanks People! "The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman #7 2007-03-14 14:39:13
Re: Degree of an ExpressionHey, just thought I might mention. I recall reading that in multivariable equations, the degree of each term is the sum of the exponants of the variables in the term, and the degree of the expression or equation is equal to the degree of its highest degree term. A logarithm is just a misspelled algorithm. #8 2007-03-15 01:10:50
Re: Degree of an ExpressionSo, xy would be order 2 then? That makes sense. Why did the vector cross the road? It wanted to be normal. #9 2007-03-15 04:41:11
Re: Degree of an Expression
especially if you consider a system of equations such as xy = 2 and y = 2x + 3, substituting you get y = 4/y + 3 which becomes y^2 - 3y - 4 = 0 which is obviously a 2nd degree equation. A logarithm is just a misspelled algorithm. #10 2007-03-15 08:41:03
Re: Degree of an Expression
Is that because you were mostly taught that? Do you think I will also confuse most people? "The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman #11 2007-03-15 09:04:40
Re: Degree of an ExpressionHmm... in my math books "ln" was always used for base e, and "log" was assumed to be base 10 when no base was given. However, in programming "log" itself tends to go by base e. So I guess it depends on what you're familiar with. At any rate, I think people from both fields will recognize "ln" so maybe you should use that. Or at least display what base you are using. A logarithm is just a misspelled algorithm. #12 2007-03-15 09:55:14
Re: Degree of an Expression
Pretty much. That's what I was taught when I was first introduced to logs, and I've just stuck to it. I don't know which is used most throughout the world though. Why did the vector cross the road? It wanted to be normal. #13 2007-03-15 10:04:14
Re: Degree of an ExpressionIn "advanced" texts I notice that "log" is used instead of "ln". I'm not sure why they don't save themselves a letter and stick with "tradition", but I can see how they justify replacing the base 10 log notation with base e: base 10 logarithms just aren't that commonly used farther down the road. I think that ln is the clearest notation though. Is ln used in England? Last edited by Zhylliolom (2007-03-15 10:05:00) #14 2007-03-15 11:16:46
Re: Degree of an ExpressionI'm from England, so yes. Why did the vector cross the road? It wanted to be normal. |