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#1 2006-05-14 19:32:02

4littlepiggiesmom
Member
Registered: 2006-01-09
Posts: 42

Solving the Equations with Square Roots(SQRT)

(Sqrt)of (3/2X-5) -10=(2/5)

I keep coming up with 6 but I don't think it's the right answer......Any help would be great ! Thanks to all.....
Happy Mother's Day to all the Mother's on here! wave

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#2 2006-05-14 19:41:22

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,908

Re: Solving the Equations with Square Roots(SQRT)


or
?
you usually solve equations of this kind:
,
by squaring the both sides and assuming that
(we are talking for REAL solutions):
and

Now, consider the first equation:

, which is >0. So for x we get:

Last edited by krassi_holmz (2006-05-14 19:52:31)


IPBLE:  Increasing Performance By Lowering Expectations.

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#3 2006-05-14 20:08:43

4littlepiggiesmom
Member
Registered: 2006-01-09
Posts: 42

Re: Solving the Equations with Square Roots(SQRT)

Thanks for the help but I used the wrong number after the = sign it should read

(Sqrt)of (3/2X-5) -10=-8 so I get
(sqrt) of (3/2x-5)=2 so then I get
3/2x-5=4 then
3/2x=9 then
3x=18
x=6

Thanks a bunch for the help! K

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#4 2006-05-14 20:11:53

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,908

Re: Solving the Equations with Square Roots(SQRT)

That's right.


IPBLE:  Increasing Performance By Lowering Expectations.

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#5 2006-05-14 21:00:39

4littlepiggiesmom
Member
Registered: 2006-01-09
Posts: 42

Re: Solving the Equations with Square Roots(SQRT)

thanks again!

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