You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**Primenumbers****Member**- Registered: 2013-01-22
- Posts: 131

**Assumptions:**

1. There are regular gaps of **4** between primes

2. These gaps of **4** have varying remainders for 4, (either 1 or 3)

A= 3x5x7x11x13x17............(x next prime in series)

x = the next prime above highest prime in A used

p and p+4 are prime

(A - p)/2 = twin prime

(A-(p+4))/2 = twin prime

**Example:**

A= 3x5x7= 105

x=11

A has remainder=1 for 4

2 Primes = 67 and 71

67 and 71 have remainder=3 for 4, which is different from A

(105-67)/2 = 19

(105-71)/2 = 17

Twin primes!

*Last edited by Primenumbers (2015-11-08 06:32:20)*

**"Time not important. Only life important."*** - The Fifth Element 1997*

Offline

Pages: **1**