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**jacks****Member**- Registered: 2012-11-21
- Posts: 80

{A} Total no. of positive integer ordered pairs of

which satisfy{B} Total no. of positive integer ordered pairs of

which satisfyOffline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,240

Hi;

There are 6 ways for 120 and 2 ways for 2013.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**jacks****Member**- Registered: 2012-11-21
- Posts: 80

Thanks Bobbym would you like to explain it to me, Thanks

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,240

Hi;

As far as I know there is no known formula for these problems. The latest work only provides a bound, not an exact answer. These had to be computed for both numbers.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**jacks****Member**- Registered: 2012-11-21
- Posts: 80

Yes Bobbym I need upper bond.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,240

Hi;

Unless I am misunderstanding their paper they have only established an upper bound for

n >= 2r

this is almost useless for your question.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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