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**mom****Member**- Registered: 2012-04-25
- Posts: 94

Find the equation of the line passing through the point (-2,5) and parallel to the line y=2x-3.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,509

Hi;

y - 2x = 9

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**mom****Member**- Registered: 2012-04-25
- Posts: 94

the options that I have are as follows:

y=-2x+1

y=-2x+3

y=-1/2x+4

Being that it is parallel, I thought that it was y=-2x+1. Would this not be correct?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,509

No, none of those lines are parallel to y = 2x - 3

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**mom****Member**- Registered: 2012-04-25
- Posts: 94

thanks

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**mom****Member**- Registered: 2012-04-25
- Posts: 94

that was actually supposed to be y=-2x-3

find the equation of the line passing through the point (-2, 5) and parallel to y=-2x-3

y=-2x+1

y=-2x+3

y=-1/2x+4

y=2x-1

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,509

Hi;

In that case the answer is y=-2x+1.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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