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You are not logged in. #1 20130319 20:52:46
Conditional probabilityProbably an easy one for many of you out there... #2 20130319 20:57:04
Re: Conditional probabilityHi;
Welcome to the forum. Do you understand the hypergeometric distribution? Last edited by bobbym (20130319 21:01:28) In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #5 20130319 22:33:24
Re: Conditional probabilityThe hypergeometric distribution is for sampling without replacement. winners = 4 ( there are 4 kings ) population = 52 ( 52 cards in the deck ) trials = 40 (40 draws ) k = 4 (you want all 4 kings ) For 2) I will need more information. Last edited by bobbym (20130319 23:02:12) In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #6 20130320 01:45:23
Re: Conditional probabilitySo what about replacing them in the deck? #7 20130320 06:15:06
Re: Conditional probabilityHi;
I am sorry, I am not following you. Please be a bit more specific. An example would be nice. Last edited by bobbym (20130320 06:38:18) In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 