Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

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**limpfisch****Member**- Registered: 2012-05-08
- Posts: 11

r(t) = ((4cost)^3, (4sint)^3) for -pi<=pi

i tried just finding T(t) by using r'(t)/|r'(t)| but i keep getting a giant mess which is no good given i have to find the normal vector and curvature later. Please help.

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**sameer mishra****Member**- Registered: 2010-08-27
- Posts: 64

i am having one idea i.e first obtain locus of above coordinate system

x^2/3 +y^2/3=16 now obtain dy/dx for this curve that comes out to be -tan(t)

now obtain equation of tangent to this curve

but what i understand that you want to apply concept of gradient in above problem but that always gives equation of normal

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