Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

- Index
- » This is Cool
- »
**0 = 1**

Pages: **1**

**Zach****Member**- Registered: 2005-03-23
- Posts: 2,075

You know, I needed to post.

It's an addiction.

0! = 1.

Boy let me tell you what:

I bet you didn't know it, but I'm a fiddle player too.

And if you'd care to take a dare, I'll make a bet with you.

Offline

**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

0! was defined during the following conference between the world's finest mathematicans:

Seriously though, the best argument for this is that 3! = 3 x 2!, 2! = 2 x 1!, so 1! = 1 x 0!, meaning 1=1 x 0!, meaning 0! = 1.

*Last edited by mathsyperson (2005-11-22 04:08:26)*

Why did the vector cross the road?

It wanted to be normal.

Offline

**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,631

3! = 3 x 2!, 2! = 2 x 1!, so 1! = 1 x 0!, **so 0! = 0 x (-1)!** ????

Negative factorials are undefined, but then some of the greatest advances in math have occurred when people have thought, "yes, but what if it **was** possible?" ... for example imaginary numbers, and fractals (fractional dimensions).

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

Offline

**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

If 0! = 0 x (-1)!, then (-1)! would be 0! / 0, which is indeed undefined. The pattern still works!

Why did the vector cross the road?

It wanted to be normal.

Offline

**wcy****Member**- Registered: 2005-08-04
- Posts: 117

it is essential that 0!=1 in combinatorics, otherwise a lot of things won't work

Offline

**martian****Member**- Registered: 2005-11-21
- Posts: 14

0 = 1

and I can prove it and thus destroy mathematics for eternity ..... mauh hah ha ha ha ha

watch little kiddies as your perfect maths fails horribly

1 = -1 x -1 (I think we get that)

√1 = √(-1 x -1) (square root both sides)

= √(-1) x √(-1) (square root distribution rule)

= i x i (" http://www.google.com.au/search?q=square+root+of+-1 ")

= -1 (" http://www.google.com.au/search?q=i+multiplied+by+i ")

1 = -1 (√1 = 1)

1+1= -1 + 1

2 = 0

2/2 = 0/2

1 = 0

and there you have it!!! MATH IS DESTROYED MAUH HA HA HA H AH

Offline

**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

Very good. I think the flaw is something to do with square roots needing a ± stuck to them, but still, it's a nice 'proof'.

*Last edited by mathsyperson (2005-11-22 04:10:46)*

Why did the vector cross the road?

It wanted to be normal.

Offline

**kylekatarn****Member**- Registered: 2005-07-24
- Posts: 445

You are wrong.

http://en.wikipedia.org/wiki/1%3D0

*Wikipedia saves the day.*

Offline

**martian****Member**- Registered: 2005-11-21
- Posts: 14

Yes, I am indeed. lol

Well done. heheh

I did know that my (deliberate) error is the (square root distribution rule) line.

Offline

**Roraborealis****Member**- Registered: 2005-03-17
- Posts: 1,594

Oh, wow! That is so cool.

School is practice for the future. Practice makes perfect. But - nobody's perfect, so why practice?

Offline

Pages: **1**

- Index
- » This is Cool
- »
**0 = 1**