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You are not logged in. #2 20081201 02:06:33#3 20081201 15:45:44
Re: the remainderI thought the question was whether 6^83+8^83 is divisible by 14. Character is who you are when no one is looking. #4 20090519 21:07:37
Re: the remainderJaneFairfax, to Thank You. Fruityloop. Last edited by Fruityloop (20090519 21:08:36) The eclipses from Algol (an eclipsing binary star) come further apart in time when the Earth is moving away from Algol and closer together in time when the Earth is moving towards Algol, thereby proving that the speed of light is variable and that Einstein's Special Theory of Relativity is wrong. #5 20090519 22:09:58
Re: the remainderI took out the first odd power of 7 (which is 83×7). The remainder is a sum of terms involving – which is equal to 7 times the sum of terms involving Last edited by JaneFairfax (20090519 22:13:09) #6 20090519 23:15:15
Re: the remainderOk. I was trying to remove the highest power of 7 in the binomial expansion, (7^83). Instead of 7*83 which is the lowest odd power of 7 remaining. In the answer you don't have to worry about the second part of the sum because it is a multiple of 49. Very good. I think I finally understand. The eclipses from Algol (an eclipsing binary star) come further apart in time when the Earth is moving away from Algol and closer together in time when the Earth is moving towards Algol, thereby proving that the speed of light is variable and that Einstein's Special Theory of Relativity is wrong. #7 20091020 19:01:02
Re: the remainderHi; We are looking for modulo 1 or 48. We are done because 6*6^6 = 6^7 which is 48 mod 49. What is so special about 48? So the answer is 35. The explanation takes longer than doing one of these. Last edited by bobbym (20091020 19:04:52) In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 