Math Is Fun Forum

Nicely done!

a = √d/be

is the square root sign just over d or is it over d/be?

if it just over d, here is the re arranged formula:

a*be = (√d)/(be) * be
abe = √d
(abe)^2  = (√d)^2
a^2*b^2*e^2 = d or d = (abe)^2

if the square root sign is over d/be, here is the rearranged formual:

a = √d/be
a^2 = (√d/be)^2
a^2 = d/be
a^2 * be = d/be * be
a^2 * be = d

To find the mid point of AB. You add x co-ordinates of A and B and divide by 2. This gives you the x co-ordinate of the midpoint M. then add the y co-ordinate of A and B and divide by 2.

M should be (2,7).

For P: I m not sure but this should work. Add the x coordinate of A and C divide by 3. this should be x coordinate of P and then repeat for y co-ordinate.
i get (10/3,2) for P.

Lets see what bobbym says. I know M is correct but i m not sure about P.

C25

wats sin, tan, and cos of 2pi/3?
watever is not is your answer.

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they survive radiation, being frozen and a lot more!

1 more question...

A person of mass 70kg jumps up and lands on a scale, causing the scale to read 750 N. Find the persons weight and acceleration.

I think i solved it but i m not sure if it is correct. All unit are SI so theres no constant k.
i did:

force = mass * acceleration

i used that formula to find the acceleration:
750 N = 70kg * a
a = 10.71m/s^2

to find weight i first found out the force if the person hadnt jumped.

F = m * a
F = 70kg * 9.8m/s^2
F = 686N

then i used that to find 'm' in the equation, but using the acceleration from above.

686 N = m * 10.71m/s^2
m = 64.1 kg

I m not sure if this is the right way to find the weight and acceleration of the person. Pls comment if u find anything incorrect.
I m unusure of my answer because i use the equation to find weight when the equation has mass in it. But thats the only equation we are to use to solve this except Fnet = Fa + Fg+....

Thx in advance,

C25

Hahaha MIF...JFF come vist India.

Hi everyone!

Welcome to the forum.
I will see ya guys around.