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For now, we can use wind and solar energy and hydrogen cells in our cars and steal the energy out of the air flow etc. Perhaps make our meatings on the internet. You know, simple things. Like "don't waste your waste in the sea, or the sea will become a waste" That sort of things. Should be fairly simple
Yes, that is sad. What did I tell you? Stop with carbons as you stopped with freons
Yes, It's called termodynamics.
I'm going to watch it this evening. 18:30 gmt+1
There is a continent under the ice, if the ice melts, it flows down into the water. Or so I've heard. I've also heard that dinosaurs lived there. Also, the ice might be thicker then the sea level etc. I don't know if that's the case.
Which country?
Perhaps I will see Eragon. I will call my mom right now.
In the same way that we stoped using freons, in the same way we should stop using carbons
Thank you for showing us this though, I'd almost forgotten all about it!
http://www.mathsisfun.com/forum/viewtopic.php?id=5066
and
http://www.mathsisfun.com/forum/viewtopic.php?id=2042
It was my thought that alot of these kinds of questions sticks together, and has the same sort of solution incommon, just like people comming here to find solutions to problems, oftenly needs the principles and wont find the special case unless she posts it herself, and if she does, she wants help as soon as possible. So if you want to connect her problem to a thread, mostly, the search will be more easy if there is only one thread with the problem and she will find more response then you put time in there. If you had some sort of combo mode where you could see the first post in every thread and connect them. It would be interesting since you probably would understand some of the replies explaining. And it might be fun work, unless ofcourse it would be totally boring.
Could understand how it would. But I've had my say in this. Thank you!
Must help gnitsuk... Wrote:
Should be:
This is not good. Personally, I think the equations are a wee bit harder then the numbers
I would also like to add that i remember a certain rule (r(cos(Q) + isin(Q)))^p = r^p(cos(pQ)+isin(pQ))
I would like to have that verified.
Would it be simpler for you if I wrote C --> E, E = C-a?
Well, it's true isn't it? First C and then C-a does mean C-->C-a. even though the leap is a and even if a has an identity.
Don't think so. C and C-a must always be a finite distance away from each other, no matter what the value of C. What do you mean "a has an identity"?
Honestly, I haven't been able to make it even a quarter of the way through your first paragraph of your first post because the time I get there absolutely nothing is making sense.
I guess you think I'm just a "crackpot" kind of guy.
No, well, not yet anyway. I just think you're having a real hard time communicating.
So you are saying that you cannot remove a from C. Then you cannot remove, for instance, a branch from a tree or a penny from a wallet. That's what I meant. Think of C as a unit, made from smaller units If you remove a from the unit, then most of the unit remains. Makes sense?
The finite distance thingy, what's that all about? If a goes to outer space, does C become C minus a then?
How to combine multiple topics with same problem, any thoughts? Making combo threads might be interesting.
If for instance the moderator had a "combo choice" mode in which he selected 2 threads and pressed a "combine" button. The author would then become a 2 value matrix just as I explained in my post in introduction here: http://www.mathsisfun.com/forum/viewtopic.php?id=5362
But I don't know if it's needed.
A possibly more efficient way of doing things would be to introduce new types of post icons.
Right now, there's a blue box next to any topic that has new posts in it. In the same place where that goes, some kind of icon could be introduced to indicate that "this topic is unresolved". All topic in Help Me would start off like that, and then once the topic creator is happy that his problem has been solved, he can tick a box somewhere to get rid of that icon. It'd probably be best if moderators had that ability as well, in case the topic creator forgets to or something.
Would this be possible to implement?
Exactly! And if the same problem is resolved in another thread, then simply link thread 2 to thread 1, or even better, cross them into a third thread and delete the 2 original treads, then you give the author of thread 3 the matrix A=[author1, author2], so that you don't have to have like -A MILLION- threads. Whatcha say?
The thread name could also be a matrix: you simply give every post in thread 3 its origin at top ie. the thread name in other words topic.
A moderator could also give every cross thread a cathegory name of his likeing.
Well, it's true isn't it? First C and then C-a does mean C-->C-a. even though the leap is a and even if a has an identity. Somehow, I imagine it works. But anyway, if you have a better way, just tell me. I'd be happy to change some. I'm thinking of this nD world. It's a dot with under(n)-dimensional dots that smear together seen from that dimension. As a (big) nD dot. So that's how all particles can have the same identity, simply say they (the particles) were you all the time, connected by gravity for instance, and if so, that q(neurons,mass,charge,distance,position,time) is actually a matrix q(particles,mass,charge,distance,position,time) that connects all thing, just a teenyweeny bit, and that truelly, the conclusion that the force does the self, is self sustaining since all mass effects eachother with a force.
"f(ns) has only incommon with f(xs) the force that keeps the self together, the force that binds it, any other function f(ns) would not be f(xs)." And since the force keep all things connected, the mass does not need an identity since they are all part of the same self, even though the self cannot notice or comprehend in particular that we are interconnected even though we are by force and hence physically and that's the only cind of interconnection there is. So given that it is the force that binds us that makes us ourself and anything itself since proven force is the function "self" and not for instance position since it is not incommon for all parts of the self, and momentum would not change the fact, since it would need to be an incommon factor and if the self would have that, then everything would have that. But that would be impossible since they would probably need to share vector 2
I guess I make little sense to you. Have you read it all yet? I guess you think I'm just a "crackpot" kind of guy. But you know, I've thought about this for a long time. Probably some (if not to say most of it) make sense. If you know how I use the math "tools".
You've been like a good friend, debating this here. Thank you so far.
(Note: that's a friendship kiss, well a smack on the sheek really)
And I hope you slept well, i guess you went to bed soon after you posted that. I know I did, gmt+1
Anyway, 184 views, Awesome! That's about as many views as i got on the other forum on 1 + 1/2 month!
On my best thread!
I must have posted something something -DOH- . Hehe.
Hrhrrm, OK attention please!
I'm assuming subtraction of neurons just means subtraction of the number of neurons?
D is a function/matrix that loose its matrix value
How exactly does something lose it's matrix value, what is a matrix value, and what does D become when this happens?
D is a function/matrix that loose its matrix value if C would sease to exist (vaporise, dissapearing without leaving a trace)
But I thought C was the number of neurons. How is it that a number can cease to exist? Do you mean that C neurons cease to exist?
C --> C-a=E, D(C) = D(C-a), you loose one neuron, but you do not loose your self.
E --> E+b, D(C) = D(E), you gain one neuron, but you don't loose yourself.Why the "C -->" and the "E -->"? What are you trying to say here? Typically, arrows imply and if-then statement. That doesn't seem to make sense here.
1.The arrow means "eventually reaches" as in the lim(x-->100) stuff.
2.C is the neurons, they cannot cease to exist, but given that they did, the matrix D would become the empty matrix [], and it does so because the function in every cell of the matrix looses its value.
I'd be happy to answer any more of your questions, just ask on. I hope there is reason to believe me. In some points. Go on Ricky, post ahead!
We might even save the world. Or we might blow up the world and survive as being stupid matter. Both choices are OK!
You're using things you aren't defining.
let's say that a part of the brain is the self, D, and that this brainpart has C neurons.
C --> C-a=E, D(C) = D(C-a), you loose one neuron, but you do not loose your self.
E --> E+b, D(C) = D(E), you gain one neuron, but you don't loose yourself.How is it that D is a function? What is a and b? What is E?
a and b are single neurons, D is a function/matrix that loose its matrix value if C would sease to exist (vaporise, dissapearing without leaving a trace), It is probable that it is a multiple to the self, this allready explained i won't venture further here. Hence D is a matrix that requires C. Sorry for taking time, I pressed ctrl-z. Anywho, where were I?
The matrix value, is at any given time the current matrix D(xs)
Where exactly is the shortcut in this, can you tell me?
Oh, no i missed startrek, the world is comming to an end!
(Kidding)
I guess we are all just an n:dimensional solution.
Definitely so, Ricky! In my proposal, the self is not a direct function or matrix of the n particles/masses, but rather a function/matrix q(neurons,mass,charge,distance,position,time) that remains from t1 to t2, this is deep stuff, i have to think hard. In short D is not (=/=) q(ns or xs) unless q(ns) = q(xs), that is the self is the function that -may- remain from q(neurons,mass,charge,distance,position,t1) to q(neurons,force,distance,position,t2). Since the only function which may do that for a longer time is force that is incommon to the entire self, it is obvious that the self will remain even though you die -given that any force will do-. The interaction will remain in such a case, given that force size only defines the size of the self ie. impact. If there was something in my thesis that was unclear then I would appreciate if you said so.
That D(C) = D(E or F) is my way of describing that D[u1,u2,u3...] = D[w1,w2,w3...] or that the neuron matrice is independent of the self if you exchange few enough neurons, but clearly the self cannot be in the braincell you take away, so D must surely be proportional to neurons existing, but that does not define the self, more then where it is and how big it is, unless you have other factors. I hope I'm not being to serious for your taste. Hope I'm being social enough.
thank you Ricky, for telling me and if you still consider me wrong after the edit, then just say so. In an additional reply.
*Further edits have been made*
You liked the proof, simron? Thank you!
And Ricky, are you Richard as in "Richard's paradox" in wikipedia? Myself I've never heard of it, but it did make sence. What is the paradox really reffering to? What is metaphysics and what's it got to do with what?
Awesome, And it doesn't say that little extra that makes it all crackpot! Never thought I would find that.
Overall, e^(ln(x)+1)=e^(ln(x) + 0)*e^n(0+1). the 0 can also be dealt with as the 1, in fact any additive number n in the exponent means an added multiple q^n
As you can see, when this is given, all equations that means e^(ln(x)+1)/x is e.
I 2 used the simple trick that (days-(q+1))/7 can be ≥ 52 for 2 values of q, 0 and 1, and q can only have 7 values, 0,1,2,3,4,5,6. So in 2 of seven cases every fourth year the equation yeal ≥ 52, and the other 3 years, only one value of q (0) makes the equation yeal ≥ 52.
And I figured that someone would speak about leapy being 97/400 chance or so. Normaly, such things are not taken into consideration in 7:nth grade though. Yah know.
And i think there is no conspiracy about it all really. This we wrote should work.
Sure you can. Even though I've tried myself but it didn't work. It might do now though.
You figured out this math problem of yours, suha? The one in help me?
You want number of sundays as a function of days?
sundayless days in first seven days = q (q(max) = 6)
days in a year = days
1+ (days-(q+1))/7
This is a matrix (a mathematical matrix, that is). If (days-(q+1))/7 ≥ 52, then you have 53 sundays
for days = 365, the chance is 1/7*100%
for days = 366, the chance is 2/7*100%
the chance for days to be 366 is 1/4
the chance for days to be 365 is 3/4
(1/4*2/7 + 3/4*1/7)*100 = 17,857% (=1/5.6 or 5/28)