You are not logged in.
here is another similar joke
Knowledge is power
power=knowledge
Time is money.
time=money
But power=work done/time
knowledge=work done/money
money=work done/knowledge
Moral of the equation:As the knowledge of a person approaches 0, the money he earns approaches infinity, regardless of the amount of work done!
funny?
The sum of the lengths of any two sides is greater than the lenght of the third side.
For all triangles,
by cosine rule,
c²=a²+b²-2abcosC
(a+b)²=a²+2ab+b²
a+b=√(a²+2ab+b²)
c=√(a²+b²-2abcosC)
now, a+b is definitely larger than c, as the maximum possible value of -2abcosC is less than 2ab, as angle C is smaller than 180 but larger than 0.
what is a halfling??
if the ellipse is not centred at the origin, the equation becomes,
(x-p)²/a² + (y-q)²/b² = 1
where (p,q) is the centre
then,
RHS=b²+2b+1= (b+1)²
but what abt LHS ?
here is a proof for right angled triangle:
by pythagoras theorem,
a²+b²=c²
c=√(a²+b²) ----(1)
(a+b)²=a²+2ab+b²
a+b=√(a²+2ab+b²) ----(2)
comparing (1) and (2),
one can see that
a+b>c
is it possible to use some general method as outlined by Euclid
Another simple way of doing it is to let x=0.9999999
then, 10x=9.9999999999
Equation (2)-(1),
9x=9
x=1
I am not sure if this is mathematically correct
How do we prove that the sum of the lengths of any two sides is greater than the lenght of the third side in the first place?
Just interested.
ok thanks
i have some trouble proving this vector question:
The points A,B,C,D have position vectors a, b, c, d with respect to the origin O. The position vector m, of M on AC such that xAM=yMC, where x+y=1.
Show that if A,B,C,D are points on a sphere, centered at O, and if AC meets BD at M, where x¹BM=y¹MD with x¹+y¹=1, then
xy|a-c|²=x¹y¹|b-d|²
(bolded letters are vectors)
Physicist joke
There was a serious case of a bird flu and three scientists were called to investigate.
The biologist dissected the chicken and checked for any virus in the chicken.
The chemist went to the neighbouring river and checked for any poisonous chemicals in the river.
The physicist just looked at the chicken and said, "Assuming that the chicken is a perfect sphere..."
i wanna be a teacher next time!
teaching rox!
here are some tips to remember square root of large numbers..
you can break up the square root into two or more parts, eg
√36=√4 x √9 =2x3=6
that way, you need to remember less values
but this can only work for some numbers
Do any of you have cool graphs plotted by some computer program (eg. graphmatica)
Does anyone know how to plot a star shaped graph?
i created a base converter before,
maybe it might be useful to convert your integers to other bases (eg base 16)
http://www.geocities.com/chengyuanwu/baseconverter.html
Answer:
well, it is not meant for real encryption, just for fun!
there is another encryptor that can encode into special Chinese characters:
eg:
琶抢楸楸⫸ὀ暊煈ὀ暊灎ὀ歬汦煈ὀ橲抢庺歬煈ὀ掜汦潔ὀ潔抢庺楸ὀ抢歬悮潔瘪浠煈暊汦歬⫸ὀ构牂灎煈ὀ掜汦潔ὀ掜牂歬ಲৄಲৄ煈斐抢潔抢ὀ暊灎ὀ庺歬汦煈斐抢潔ὀ抢歬悮潔瘪浠煈汦潔ὀ煈斐庺煈ὀ悮庺歬ὀ抢歬悮汦憨抢ὀ暊歬煈汦ὀ灎浠抢悮暊庺楸ὀ䅮斐暊歬抢灎抢ὀ悮斐庺潔庺悮煈抢潔灎㢤ಲৄಲৄ
again, it is not really secure since one symbol only codes for one letter
are you out to punish all of us with your puns??
i suspect that it is illegal to square root both sides, since square rooting a negative number is not allowed
Answer: visit http://www.geocities.com/chengyuanwu and visit Encryptor 6 and use password 2,2
i created a program to analyse the frequency of letters and punctuation in English (related to statistics in maths):
http://geocities.com/chengyuanwu/adv_frequency_analyser.html
As expected, e is the most common letter
Here is one sample report:
Total no. of different characters: 74
1) " "---195(enter)
2) " "---195
3) " "---1026(space)
4) "!"---1
5) "'"---4
6) "("---29
7) ")"---29
8) ","---21
9) "-"---73
10) "."---58
11) "/"---2
12) "0"---9
13) "1"---17
14) "2"---8
15) "3"---12
16) "4"---10
17) "5"---12
18) "6"---8
19) "7"---10
20) "8"---9
21) "9"---9
22) ":"---17
23) ";"---1
24) ">"---1
25) "a"---509
26) "b"---55
27) "c"---184
28) "d"---173
29) "e"---512
30) "f"---73
31) "g"---106
32) "h"---138
33) "i"---351
34) "j"---20
35) "k"---61
36) "l"---204
37) "m"---101
38) "n"---343
39) "o"---305
40) "p"---73
41) "r"---328
42) "s"---379
43) "t"---311
44) "u"---140
45) "v"---33
46) "w"---83
47) "x"---11
48) "y"---60
49) "z"---13
50) "|"---3
51) "©"---1
52) "»"---13
53) "ç"---6
54) "é"---5
55) "ñ"---6
56) "ö"---5
57) ""---1
58) "中"---7
59) "体"---2
60) "台"---5
61) "国"---5
62) "文"---2
63) "日"---6
64) "本"---6
65) "港"---5
66) "灣"---5
67) "版"---15
68) "简"---1
69) "繁"---1
70) "語"---1
71) "香"---5
72) "국"---6
73) "어"---1
74) "한"---6
i²=-1
(-1/1)= (1/-1)
(i²/1)= (1/i²)
√(i²)/√1= (√1)/(√i²)
i/1= 1/i
i²= 1 (cross-multiplication)
Contradiction!!
How to solve this paradox?
I also don't know the answer.
There are three switches and one light bulb, which is kept in a locked room. You are only allowed to go into the room once. How do you tell which switch controls the light bulb? (there is only one such switch)
Here is a challenge to decode the following text (in english):
158:198:236:212:68:150:234:68:144:238:224:68:144:226:232:238:222:30:24:140:214:234:202:238:
234:234:214:226:224:68:198:200:226:238:236:68:222:198:236:212:92:68:228:238:248:248:220:206:
234:92:68:210:198:222:206:234:68:198:224:204:68:208:238:224:96:68:30:24:30:24
Hehe, have fun!