Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**wcy****Member**- Registered: 2005-08-04
- Posts: 117

i²=-1

(-1/1)= (1/-1)

(i²/1)= (1/i²)

√(i²)/√1= (√1)/(√i²)

i/1= 1/i

i²= 1 (cross-multiplication)

Contradiction!!

How to solve this paradox?

I also don't know the answer.

*Last edited by wcy (2005-08-07 01:42:27)*

Offline

**kylekatarn****Member**- Registered: 2005-07-24
- Posts: 445

I've already discussed that on IRC and nobody could explain that too..

Offline

**wcy****Member**- Registered: 2005-08-04
- Posts: 117

i suspect that it is illegal to square root both sides, since square rooting a negative number is not allowed

Offline

**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,555

"How wonderful that we have met with a paradox. Now we have some hope of making progress." - Niels Bohr

I suspect it is this curious phenomenon:

(-1)² = 1²

-1 = 1 ...?

Making:

√(i²)/√1= (√1)/(√i²)

i/1 = 1/i ...?

Because:

1/i = (1 x i) / (i x i) = i/i² = i / -1 = -i

* basks in glow of very rare victory, hoping it lasts *

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

Offline

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,218

wcy wrote:

(i²/1)= (1/i²)

√(i²)/√1= (√1)/(√i²)

Normally, in such paradoxes, this is where the mistake lies.

Since a² = b²,

it cannot be inferred that a=b.

Taking square root on both sides of an equation should always have the

'±' sign, after the square root is worked out.

Character is who you are when no one is looking.

Offline

Pages: **1**