Math Is Fun Forum

Multiply the second equation by yz then subtract itbfrom the third equation.

If there are x0, y0 and z0 for those, then those are the only ones, because sin(3 theta)=cos(3 theta)

It makes no difference.

What about Ubuntu?

Yeah, but it was easier to just find a pic on the interblag than to make it in GG or anywhere and upload it on imgur.

There isn't such an algorithm.

Consider the corners of the cube:

After each move, some of the odd labeled corners go into places of even labeled corners and vice versa. So, after any odd number of moves, odd corners end up in even numbered places and the even corners end up in odd numbered places, so such an algorithm is not possible.

Abort works for me too.

I'm sure that if you post the proofs here someone will be able to respond.

The one you posted looks good (assuming I got what you meant to write; some parentheses are missing), but it generally depends what you assume you already know is true, like you said.

Hm?

Yep! It's interesting, to say the least.

Hm, does the first meaning of boffin vary from context to context, because a nerd is not the same as a geek.

What are x and y?