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Blah!
i say from now on, if the person is alive, we use a binary search to pinpoint his/her exact age in the first seven questions!
I know so little about rock artists, I can't even think of what to ask now! ![]()
the Cauchy-Schwartz inequality - its everywhere!
yeah it was!
15. Is he over 40 years old?
incidently, what are you persuing, Ricky? A masters?
14. is his primary music style rock?
12. is his primary music style classical?
To mikau,
I never said Einstein was not involved in mathematics.
but but...you DID!
post#6 by MathsIsFun "Was he involved in Mathematics?"
post#7 by ganesh: "No."
Einstein was not involved in mathematics? ![]()
hahahahaa...
Chapter 2.
Well that kid was a lot of help, Fred thought as he walked down the hall from his last class. "Yeah I know about it!" he says. What can he tell me? "um...idk, lol!", i've gotten clearer answers from highschool chics on instant messenger. "ZOMG NO!"
But I guess it was stupid of me to ask, Fred thought as he reached the end of the corridor and rounded a corner in the direction of the cafateria. He stopped abruptly. Standing before him was a young vagabond that closely resembled The Artful Dodger from oliver twist.
"Why are you interested in the Class of Darkness?" he said in a raspy voice.
"Who are you?" Fred asked.
"The artful dodger from oliver twist!"
...did he just read my mind?
"why do you want to know about MY class?" he asked
"YOUR class?" fred asked nervously "I didn't know it was-"
"well since you are obviously DYING to get in, i guess I can make room for one more!"
"No no, i didn't say I wanted to"
"our class is in room C4 39 at 10:00 o'clock, don't be late!"
"But there is no fourth flo-'
"DON'T BE LATE!"
"i'm NOT JOINING YOUR CLASS!" fred wheeled around and dashed away.
The following morning, Fred arrived on time for his vector calculus class at 10:15 am and sat down, still feeling shaken by the mysterious encounter. "15 minutes late" said a familiar raspy voice. Fred looked up and nearly jumped out of his chair as he saw the artful dodger seated at the teachers desk. He then noticed he was surrounded by many of the reportedly missing students. "where is Mr. McGinnley?" fred yelled. His eyes fell on a large jar on the desk that housed a human head. "hh..HOW long has that been there?" fred asked another student, clutching the desk with his fingers. "about 12 years" the student replied. 'it used to be smaller'
Freds last class was yesterday.
"Well what is it there for?" fred asked again.
"Moral support" the teacher said, who had somehow heard his whispering from across the room. "he was my mentor!"
that was enough for Fred. He jumped out of his seat, leaving his books and dove for the door. SMACK! He crashed into a wall. Impossible! the door was gone. There....there was no door!
"There never was a door" the teacher sneered 'so don't trouble yourself'
Fred slumped against the wall, totally defeated. "what...WHAT IS THIS CLASS?"
"this class," the teacher explained "is about 4 dimensional space!"
okay, first we usually write x to the second power as x^2. Basically, x^n is x to the nth power.
anyway, what you have then is you must factor
x^2 -6x -16 = 0,
the question you have to ask yourself is, what two numbers multiplied give you -16 and added equal -6?
the answer is, 2 and -8, because 2*(-8) = -16 and 2 + (-8) = -6, now that you have these two numbers, here's what you do
(x + firstNumber)*(x + secondNumber)
so the factored form is (x + 2 )(x + (-8)) = (x + 2)(x-8). Note you can stick the numbers in any order you want, so you could have put -8 first to get (x - 8)(x+2) which is the same answer and just as good.
the question is, why are the cats all running left? The mouse is on the right! ![]()
i*q = 0
i'd like to demand lots of vector proof problems, please! ![]()
can't find enough of them.
Polynomial division is fun!
taken from my book:
Let V be a real vector space. Supppose to each pair of vectors u,v ∈ V there is assigned a real number, denoted by <u,v>. This function is called a (real) inner product on V if it satisfied the following axioms:
linear property: <au1 + bu2, v> = a<u1, v> + b<u2,v>
symmetric property: <u,v> = <v,u>
positive definite property: <u,u> >= 0; and <u,u> = 0 if and only if u = 0.
The vector space V with an inner product is called a (real) inner product space.
everything but the last line makes sense. What do they mean a vector space 'with' an inner product? Does this function create some sort of vector space itself? That is, is an inner product space a vector space? If so, what do the elements consist of?
8. Was his field one of the life sciences?
(from dictionary.com: Life Science: any science that deals with living organisms, their life processes, and their interrelationships, as biology, medicine, or ecology.)
Morphos has been posting nothing but premotions for some lame IQ test all over the forums.
Can we get rid of him and his posts?
why, thank you! ![]()
sure! But what says we can't put one big circle in a a square or triangle?
5. was he a scientist?
ganesh is from india? ![]()
sadly in this problem the raptor catches you almost just before he reaches top speed. In fact he'll hit you at precisley (6 + 2 sqrt(89) mps which is about 24.86. Having to use the piecewise function would have been more interesting. But you're running at 6mps so its equivilent to about a 19 mps impact. He'll probably slide at least another 4-to 5 meters on his face.
I'd like to see someone solve the three sided raptor problem though. THAT thing looks tough.
Definitely not anime. They're a stricly american cartoon i THINK. I used to watch them as a kid, they were cool! Their names were leonardo, michelangelo, raphael, and donatello.
reminds me of this: http://xkcd.com/197/
luca is creating parametrically defined lines. suppose you have the line from (a,b) to (c,d). This consists of all points of the form (x,y) = (a, b) + t[(c,d) - (a,b)] for any t you pick, this gives you the point you reach if you start at (a, b) and walk t times the distance from (a,b) to (c,d), walking directly towards (c,d). Note, if you chose t= 1/2, you have (a,b) + 1/2(c,d) - 1/2(a,b) = 1/2[(a,b) + (c,d)] which is the midpoint between the two, which is what we'd expect. Further, if we walk 1 times the distance from (a,b) to (c,d) we should end up at (c,d), and indeed (a,b) + 1[(c,d) - (a,b)] = (a,b) + 1(c,d) - 1(a,b) = (c,d).
The point is, if you pick a t greater than 1 or less than zero, you are no longer finding a point that lies partway between the two. What luca is doing is finding two parametrically defined lines that define the two given line segments. In one line, the parameter is t, in the other it is s, he is then finding for what values of t and s these two lines intersect. If either of them are greater than 1 or less than zero, then you have to 'walk outside' the two line segments in order to reach the intersection point. Why? if t > 1, then we are talking about a point that lies further than the whole distance from (a,b) to (c,d), which means they do not intersect within those boundaries. Further, if t < 0, then t is negative, which means we are starting at (a,b) and walking backwards, away from (c,d) which certainly means the intersection point does not lie somewhere between (a,b) and (c,d).
In otherwords, he is defining two infinite lines, finding where they intersect, and then seeing if the lines fall within the boundaries of the line segments.
Does that make sense? Do you understand the vector notation luca is using?