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#3 Help Me ! » Help Please » 2007-02-01 05:09:16

Neha
Replies: 3

Find y, A, and B

       \                                           120 dg /
_____\_____________________________/___>____
          \                                         29/3 /
  8        \                                              /  (3A)dg
----------------------------------------------------->------
              \                                          /
                \                                       /
                 \                                     /
      15         \                              y   /
                    \                                /
                     \                              /
-------------------------------------------------->-------
                        \                        /
                         \                      /  (5B)dg

#4 Help Me ! » Degrees » 2007-01-09 04:06:04

Neha
Replies: 2

Find Angle A if three times its complement equals 150degrees .

#5 Re: Dark Discussions at Cafe Infinity » eid mubarak » 2007-01-02 07:38:42

wow yummy....i'm starting to get hungry again smile
my eid was also great....ate alotttttttt...but gosht came late so we made that today.

#6 Help Me ! » graphing » 2007-01-02 07:37:26

Neha
Replies: 4

Graph the following function showing all x-intercepts,holes,and asymptotes:

y = x^2 - 3x / (x + 1)( x - 2)(x - 3)

#7 Help Me ! » Help with dividing! » 2006-12-28 11:16:49

Neha
Replies: 1

divide x^3 + 2x - 1 by x + 3

#8 Help Me ! » question » 2006-12-28 09:26:10

Neha
Replies: 2

Apply Descartes' Rule of Signs to determine the possible numbers of positive roots of:

x^4 - x^3 - 3x^2 - x + 2 = 0
but not sure what i did is right....correct me if i did it wrong
f(x) = +x^4 - x^3 - 3x^2 - x + 2
f(-x) = -x^4 - (-x)^3 - 3(-x)^2 - (-x) + 2
= -x^4 + x^3 + 3x^2 + x + 2

#9 Re: Help Me ! » interesting question » 2006-12-27 05:50:45

89 * (.47 - .29) = 1.14x
89 * 0.18 = 1.14x
16.02 = 1.14x
x = 14.05263158
x = 14.05 ounces

#10 Help Me ! » interesting question » 2006-12-27 05:12:08

Neha
Replies: 5

How much of a 14% peroxide solution should be added to 89 ounces of a 47% peroxide solution to get a 29% solution?

#11 Help Me ! » Help » 2006-12-26 03:58:30

Neha
Replies: 1

Write the quadratic equation with a lead coefficient of 1 whose roots are 2 + sqrt5 and 2 - sqrt5 .

#12 Help Me ! » Right » 2006-12-26 03:36:51

Neha
Replies: 1

Find the inverse Function of y = -2x + 7

2x = -y + 7
x = - 1/2y + 7/2

right?

#13 Re: Help Me ! » solve help please tryed many ways..all came out wrong » 2006-12-22 05:18:15

that wht i had also......
but its wrong
why
if u put in 11...
6 * 11 =66
66 - 2 = 64
sqrt64 = 8

then  ohhhhhhhhhhhhhhhhhhhhh myyyyyy god
lol u know hwt i did
i did teh same thing that you all did but at teh end i said sqr8 - sqrt9 lol
ohhhhh my god
thanks guys smile

#15 Help Me ! » Help Me Out Please » 2006-12-21 05:36:32

Neha
Replies: 1

Consider the equation, 4x^2 + 9y^2 - 64 + 72y + 364 = 0. Tell what conic section this represents and sketch its graph.

This is what I did:

(4x^2 - 64x. . ..) + (9y^2 + 72. . . .) = -364
4(x^2 - 16x. . ..) + 9(y^2 + 8y. . . .) = -364
4(x^2 - 16x + 1) + 9(y^2 + 8y + 8 ) = -364 + __
4(x^2 - 16x + 1) + 9(y^2 + 8y + 8 ) = -364 + 4(1) + 9(8)
4(x^2 - 16x + 1) + 9(y^2 + 8y + 8 ) = -364 + 4 + 72
4(x - 1)^2 + 9(y + 0.9)^2 = -288

[4(x - 1)^2] / -288 + [9(y + 0.9)^2] / -288 = -288 / -288

or

(x - 1)^2 / (sqrt(-72))^2 + (y + 0.9)^2 / ((sqrt(-32)) = 1

Is this correct?

#16 Re: Introductions » hello » 2006-12-18 06:31:37

thats just wrong ok guysrolleyes:

#17 Help Me ! » simplify...i did it right...right? » 2006-12-18 06:17:11

Neha
Replies: 1

simplify:     
    1
-----------
         2a
b + ------
            3
      1 + --
             c   

---------------------------
I DID

      1
-------------
b + 2a
    ----------
     1 + 3
        ------
           c


                           1
----------------------------------------
       2a                                    c
    -------------                   ----------
b + 1                 TIMES       1c + 3
    ---------------               --------------
     1c + 3                                 c
    --------------                   -------------
         c                                1c + 3


EQUALS

           1
--------------------
        2ac
b + ------------
         1c + 3


Then

          1
-------------------
b(1c + 3)+ 2ac
-----------------
       1c + 3


Then

         1                                   1c + c
        ---                          -----------------------
         1                            b(1c + c) + 2ac
-------------------  times  ------------------------
b(1c + c)+ 2ac                        1c + c
---------------                  ---------------------
      1c + c                         b(1c + c) + 2ac



Then

1(1c + c)
--------------------
b(1c + c) + 2ac

and this is my answer

#18 Help Me ! » distance » 2006-12-14 09:04:14

Neha
Replies: 1

find the distance from the point (3,-7) to the line x = -1.

this way ofcourse....!!!
y = -1x + b

#19 Re: Help Me ! » graph of the function » 2006-12-12 14:39:07

you have to graph the function...thats the question they ask

#20 Help Me ! » Am i correct ? » 2006-12-12 10:05:33

Neha
Replies: 2

in a group of sinngle mothers, 14% were on welfare while the others were employed . if 4300 were employed, how mmany mothers in this group were on welfare?

i did this..but now i think what i did isn't right. what are your thoughts on what i did :

14/100 = x/4300
100x = 60200
x = 602

#22 Re: Introductions » hi » 2006-12-09 05:28:45

its very easy.....

#23 Re: Help Me ! » Identity » 2006-12-06 04:59:36

neva mind guys i got it

sin(A + B) = sinA cosB + cos A + B
sin(A + A) = sinA cosA + cosA sinA
sin 2A = 2 sinA cosA

#24 Help Me ! » Identity » 2006-12-06 04:13:50

Neha
Replies: 1

Develop the identity for sin 2A using the identity sin(A + B)

http://www.mathwords.com/t/trig_identities.htm

use this formula
sin 2x = 2sinx cos x

or use this formula
sin(x+y) = sin x cos y + cos x + sin y

#25 Re: Help Me ! » Triangle » 2006-12-05 06:04:14

ok this is what i did:

c^2 = a^2 + b^2 - 2ab cos P
A^ = 11^2 + 15^2 - 2(11)(15)cos 65dg
A^2 = 121 + 225 - 139.4640264
A^2 = 346 - 139.4640264
A^2 = 206.5359736
A = 14.37135949
A = 14.4


NEXT

14.4/sin65 = 15/sinB
sinB = 15sin65/14.4
SinB = 0.945952038

NEXT

14.4/sin65 = 11/sinC
sinC = 11sin65/14.4
sinC = 0.012106812


CORRECT

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