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#1 2006-12-12 10:03:47
- Neha
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- Registered: 2006-10-11
- Posts: 173
graph of the function
y = (1/2)^(-x - 4)
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#2 2006-12-12 11:43:54
- mathsyperson
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- Registered: 2005-06-22
- Posts: 4,900
Re: graph of the function
What's the question here? Do you want to draw the graph, find points where it crosses the axes, find any turning points or asymptotes it may have? I can't really help you too much if you don't give a question.
At the moment, I can just give you this hint that will probably help out a bit:
Consider what happens when instead of 1/2, you write 2[sup]-1[/sup]. Then use the laws of indices to make that a simple expression as a power of 2.
Why did the vector cross the road?
It wanted to be normal.
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#3 2006-12-12 14:39:07
- Neha
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- Registered: 2006-10-11
- Posts: 173
Re: graph of the function
you have to graph the function...thats the question they ask
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#4 2006-12-12 15:20:40
- MathsIsFun
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- Registered: 2005-01-21
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Re: graph of the function
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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