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thanks very much for the help its greatly appreciated
Hi i am doing a buiolding surveying degree and have come across this log question that im stuck on as i havnt come across them before. If someone could help me out that would be great. Iv got to work out T in each case.
53=10 log (1/T)
log 1/T = 5.3
1/T=
25=10 log (1/T)
log 1/T = 2.5
1/T=
20=10 log (1/T)
log 1/T = 2
1/T=
Thanks for any help
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