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Wow. Cool to see that evolution.

While concept was forming in my head, I was wondering if functions could change (x + y)(x + y) (factoring) vs quadratic approaches so that factoring might work where it doesn't without tangents, cosines etc...However, I realized that doesn't really make sense so that quadratic equation was necessary.

That was sort of the rationale behind my original question. I realize it's sorta nonsense tho. Factoring clearly wasn't going to work. Unless I'm missing something else...which, of course, is very possible. Lol

Yup.

I just did x = b+/- blah blah to get tanx=.303 and -3.303.

So, tan^-1's =

16.86 degrees (.29 rad) and 196.86 degrees (pi+.29 rad).

And

286.84 degrees (1.28 + 2pi rad) and 106.84 degrees (pi - 1.28 rad).

Yes, that's what I meant. Thanks.

**Newman**- Replies: 6

Can this be factored or do you have to do quadratic formula?? Does the fact that it's an angle give it any unique workable properties or do I just look at coefficients like any other quadratic? Thanks.

1tan^2x + 3tanx -1 = 0

Yes!! thx

And going back to this....is this right??

Find y' when y=(x^3 + 3x^2 + 1)(x^2 + 2)

y'= 5x^4 + 12x^3+ 6x^2+ 14x

Thx

I learned that they've gone out 10^14 and haven't found integers where a^3 + b^3 + c^3 = 33

Thank you very much. Seems so obvious now. haha. Really appreciate it.

Sheesh, they seem so freakin obvious now. Haha. Thank you so much again or ur efforts to help me!

awesome! thank you. I'll study what u guyz posted.

Thanks.. Sorry, I freakin copied it wrong. Just fixed it!!

Eesh. Again, my apologies. I appreciate effort.

**Newman**- Replies: 8

If sinθ = 3/5 and 0 ≤ θ ≤ pi/2, then tanθ = ??

Again, plz explain steps. Thank you!!

**Newman**- Replies: 5

Okay, how bout this:

(2t-1)/(3t+4)=2

plz show steps

thx

how? can u plz show work?

**Newman**- Replies: 6

Okay, a few of these are killin me. Please help and show work. Thank u so much!

#'s 1,3,4 and 6 please. So annoying because I can answer similar problems but missing some things...obviously.

THANKS!!

Test Guide

**Newman**- Replies: 0

This seems like it would be very amusing for people of all levels (don't let the first few words of paper scare ya, they're basically in jest). Curious what some of the chronic heavy math users think of it. Enjoy:

PiperThesis

http://www.theliberatedmathematician.com/wp-content/uploads/2015/11/PiperThesisPostPrint.pdf

Okay, find the rational roots and if possible all roots:

2x^4 - x^3 - 11x^2 + 4x +12 = 0

And: Find y' when y=(x^3 + 3x^2 + 1)(x^2 + 2)