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## #1 Re: Exercises » Number Theory Challenges, #1 » 2016-08-27 04:12:57

Mathegocart wrote:

You know who he is in real life??

Yes

## #3 Re: Help Me ! » Geometric Series » 2016-08-19 05:30:13

That is not factual.

I didn't say that the right answer wasn't posted. I said the correct solution hadn't been posted yet.

The solution you propose is longer and requires more work.

This solution uses the defining properties of both  ellipse and hyperbola. This is shorter.

It can be shortened more because you don't even need to know

. He could've got that with EM. It is obvious that solving 2 linear equations is terse and therefore best.

## #4 Re: Help Me ! » Geometric Series » 2016-08-19 04:23:14

Next time just email me before you attempt to solve a problem that is a bit too tough for ya. I'll be glad to assist an old guy.

## #5 Re: Help Me ! » Geometric Series » 2016-08-19 03:59:20

Hello:

@bobbym, it is amazing that you didn't get the right answer for 8.  Your diagram shows you were working on the wrong hyperbola!

The red one is the right hypie.

The correct solution is not yet given so I'll put it down.

This solution uses the defining properties of both  ellipse and hyperbola.

## #6 Re: Help Me ! » Geometric Series » 2016-08-16 17:23:09

That's wrong too. All the terms are integers so you can't get an irrational answer.

Mistake is when you did

1000*1001/2-1023=49977

your calculation got all squished together

1000 * 100 (1/2) -1023 = 49977

the right way

(1000 * 1001) / 2 - 1023 = 499,477

## #7 Re: Help Me ! » Geometric Series » 2016-08-16 16:53:57

therefore required sum is 1000*1001/2-1023=49977

That's how we solved that but you've got to calculate as accurate as you think. That answer (49977) just can't be right.

## #8 Re: Help Me ! » Geometric Series » 2016-08-16 16:46:05

I wasn't able to find more than one ordered pair for number 6, x = -1 and  y = 0. What did you find ?

## #9 Re: Help Me ! » Geometric Series » 2016-08-16 16:39:36

Bobby wrote:

If you can compute it, then you understand it. Can you compute it?

``Table[FromContinuedFraction[ContinuedFraction[0.008012018027, k]], {k,2, 6}]``

{1/124,1/125,5/624,11/1373,16/1997}

## #11 Re: Help Me ! » Geometric Series » 2016-08-12 18:40:35

Hello:

@Bobby: solving the second question was easy enough but how did you do the first?

## #16 Re: Help Me ! » Digit Apartment Help » 2016-07-29 03:27:44

An apartment without a number on it? No way. The answer is 49.

## #17 Re: Help Me ! » Olympiad mathematical problems » 2016-07-29 03:19:19

@bobbym:

3) How did you get those 2 answers.The EF algorithms you gave me won't do 1 / 2.

## #18 Re: Maths Is Fun - Suggestions and Comments » About pictures in forum » 2016-07-29 03:12:21

Hello;

I'm not a member and I upload there all the time.

## #19 Re: Exercises » Mathematics Challenges, #1 » 2016-07-17 00:43:40

How about how I used the probability command with a conditional in the latter?

## #20 Re: Exercises » Mathematics Challenges, #1 » 2016-07-17 00:36:39

So what is it for 3? With replacement or not?

When you're in doubt do both.

bobbym, what do you think of the second answer?

Hello;

## #22 Re: Computer Math » Polynomial Root Finding » 2016-06-19 04:08:33

You aren't going to finish with that awful Colonel story?

## #23 Re: Computer Math » Polynomial Root Finding » 2016-06-19 04:05:25

Feels good to have everything ready cause you've already did it?

## #24 Re: Computer Math » Polynomial Root Finding » 2016-06-16 16:07:47

The front end in Mma is confusing. He needs to learn its capabilities.

## #25 Re: Computer Math » Polynomial Root Finding » 2016-06-16 16:04:31

You have your hands full m.