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#1 Re: Help Me ! » logarithms... » 2005-11-11 09:44:08
ahh sry my fault but how? can you explain it pls
#2 Re: Help Me ! » logarithms... » 2005-11-11 09:21:22
thanx alot, but in my book it says 3)=16 and 4)=1
any ideas, and also i forogot to mention that log6 2 means the base is 6..
thx!
#3 Re: Help Me ! » need explaination » 2005-11-11 06:07:14
thx alot guys
#4 Help Me ! » logarithms... » 2005-11-11 05:58:10
- pman
- Replies: 5
hi!
please, i need help with:
1) lg(1-x)+lg(1+x)=lg0.75
2) 2 lgx=lg2 +lg18
3) 2 lgx - lg4 = lg(3x + 16)
4) log6 2 +log6 3thanx for the help
#5 Help Me ! » need explaination » 2005-11-10 16:17:01
- pman
- Replies: 3
hi can someone explain in detail how to solve this kind of problem please:
1) 7*4^x = 5*9^x
2)log3 3 + log9 1you should use logarithms to solve it, thx!
#6 Help Me ! » really need help!!! » 2005-11-04 14:22:49
- pman
- Replies: 1
hi!
i´ve got this problem i cant solve
( (4x-x^2)/(9-x^2 ) ) / ( (8-4x)/(3+x) )thanx for your help!
#7 Re: Help Me ! » math problem » 2005-11-04 04:31:48
hey can someone fin a solution or not?
#8 Re: Help Me ! » math problem » 2005-11-03 11:40:40
is there a solution??
btw is that text or a picture?
i really need this someone pls help i dont have a clue!
#9 Re: Help Me ! » math problem » 2005-11-03 10:36:26
sorry i thought you could make a link like that 
the problem is ofcourse this
( (4x-x^2) /(9-x^2 ) / ( (8-4x)/(3+x) )
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