Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫  π  -¹ ² ³ °

You are not logged in.

## #1 Help Me ! » what is the sum of x and y » 2013-06-28 03:45:44

gyanshrestha
Replies: 7

three angles of a triangle are 5x+3y, 10y+30 and 3x+20
what is the value of x+y

any idea ?
this question is asked on a mathematical competition.

## #2 Re: Maths Is Fun - Suggestions and Comments » Zoomable Number Line » 2011-12-13 04:16:25

what are the uses of zoomable number line?

## #3 Re: Help Me ! » Exponents » 2011-12-13 04:09:40

answer for question no. 2 in my way.

here

squraring both sides we get

or

squaring both sides

## #4 Re: Help Me ! » Helop me to prove this trigonometry identity » 2011-12-13 03:45:16

thanks Bob

I made a mistake in the question. corrected question is

I also edited Initial post.

I check the identity for x=1,2,3, 4 and they all are true.

thanks

but is still not getting to proof.

## #5 Re: Help Me ! » Perimeter of Trapezium » 2011-12-12 03:15:55

interesting answer. Here i find that the non parallel sides are divided into 1:3 ratio.

## #6 Help Me ! » Helop me to prove this trigonometry identity » 2011-12-12 02:18:27

gyanshrestha
Replies: 4

Sorry for mistake Here is corrected questions

## #7 Help Me ! » find the lower qurtile » 2010-01-01 23:26:22

gyanshrestha
Replies: 1

how to find the lower quartile of the following data

2,5,7,9,10,11

## #8 Re: Help Me ! » how to solve » 2008-11-29 01:47:43

Daniel123 wrote:

x^2 + y^2 = 170, which is a circle centred about the origin with radius root(170). This has an infinite number of solutions.

the equations given are of two variable and for two variable equation only two equation of different condition are required
Given equations are sufficient for finding the value of  x and y.

## #9 Help Me ! » how to solve » 2008-11-28 17:23:39

gyanshrestha
Replies: 6

x(x+y)=205
y(x-y)=35

i have solve it but i want tricky answer or solving method.
plz help me

## #10 Help Me ! » help me to prove this relation » 2008-11-03 01:33:35

gyanshrestha
Replies: 0

ABCD is a quadrilateral. M and N are midpoints of diagonals BD and AC respectively. BA and CD are produced to meet at E.
Prove that area of triangle MNE is equal to one fourth of quadrilateral ABCD.

## #11 Re: Help Me ! » Find the Co-ordinates!! » 2008-11-02 00:05:42

alternative method
Let P(x,0) be the point in x-axis
Now slope of PA is (2-0)/(1-x) and the slope of the line PB is (3-0)/(8-x)
Since PA and PB are perpendicular
product of two slopes is -1 hence
{(2-0)/(1-x)}*{(3-0)/(8-x)}=-1
which on simplifying
6=-8+9x-x^2
x^2-9x+14=0
Or, (x-2)(x-7)=0
or x=2,7
Hence the required points are (2,0) and (7,0)

## #12 Re: Help Me ! » Find the Co-ordinates!! » 2008-11-01 00:08:10

let the coordinates of the point P is (x,y)
Now we can consider the points A(1,2) and B(8,3) as the points of end points of diameter of the circle which passes through A, B and P
Now the equation of the circle is (x-1)(x-2)+(y-8)(y-3)=0

Since the Point lies in the x axis, y=0
Now the above equation becomes (x-1)(x-2)+24=0
which is quadratic equation now solve the equation we get the required answer.

## #13 Re: Help Me ! » relation with circle » 2008-10-28 00:04:27

Sorry the question is wrong. And sorry for not responding for long time.

Now the question is

We know that only one circle can be drawn which passes through all the vertex of a given triangle. So i concluded that there must be relation between the sides (and hence its area) of the triangle and the area of  the circle. Is it my guessing wrong? If not what is the relation between the area of triangle and the area of the circle?

hence x=4

## #15 Re: Help Me ! » solve » 2008-03-04 02:22:31

actually the equation was given by a student of my friend and has aslo has solution that is 2a/sqrt5.
how does it come?

## #16 Help Me ! » solve for x in terms of a and b » 2008-03-04 02:14:12

gyanshrestha
Replies: 1

please  help me to solve the equation in terms of a and b

## #17 Re: Help Me ! » solve » 2008-03-04 02:11:02

then can we solve the equation in terms of a?

## #18 Re: Help Me ! » solve » 2008-03-04 02:08:25

yes and thanks  JaneFairFax
actually i am confusing on giving the exponets.

## #19 Help Me ! » help me » 2008-03-03 23:09:03

gyanshrestha
Replies: 15

i love trigonometry and   i want more  excercise on this topic specially in conditional identities. Can any one give some sites name?

## #20 Help Me ! » solve » 2008-03-03 22:51:58

gyanshrestha
Replies: 9

solve for x

autually the power is 2/3 and 1/3.
soryy for inconvinieces

## #22 Help Me ! » a shopkeeper » 2007-12-11 00:00:11

gyanshrestha
Replies: 1

a shopkeeper uses two kinds of balace.
one weights 10% and other is 10% less.
he uses first one while buying goods and second one while selling goods so that he can make profit.
now how much pecentage does he get on total transaction for the same goods?

we frens tried in our way and we conclude on differen percentage. Can anyone solve these problem with good reasonings.

best regards

## #23 Re: Help Me ! » how do you » 2007-12-07 17:21:20

good joke Identity

## #24 Re: Help Me ! » probality » 2007-12-07 17:15:42

oh sorry
i mean what is the probality of getting solved the same question when the problems is given to both at the same time.
i have edited the question above.

## #25 Help Me ! » probality » 2007-12-06 23:21:28

gyanshrestha
Replies: 3

the probality of sovling a math problem by A is 0.25 and that of B is 0.35.
what is th probality that they solve the same problem when they try to solve together?

I know how to do it. But i really dot not uderstand why i am doing so. can anyone help me please?

i did it like that
p(not solving by A)=0.75
p(not solving by B) = 0.65
P( not solving by both)= 0.4875
P(solving by both) = 0.5125

why do we first find the 3rd line?
what is wrong with by finding multiplying 0.25 and 0.35?