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#1 2007-12-30 09:13:39
- Imogen15
- Guest
Surds
I really don't understand how to go about this:
Express (1/√2)[sup]9[/sup] in the form √b/c where b and c are integers.
Could anybody help me out?
#2 2007-12-30 15:16:38
- gyanshrestha
- Member
- Registered: 2007-11-06
- Posts: 41
Re: Surds
Last edited by gyanshrestha (2007-12-30 15:17:05)
http://gyan.talkacademy.com.np
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#3 2007-12-30 16:58:24
- Ricky
- Moderator
- Registered: 2005-12-04
- Posts: 3,791
Re: Surds
You may apply the power to the numerator and denominator independently. So it becomes 1 / √(2^9) which is 1/√(2^8*2) = 1/(2^4*√2) = 1/(2^4*√2) * (√2 / √2) = √2 / 2^5 = √2 / 32
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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