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#1 Re: Help Me ! » proof » 2006-04-08 04:50:15

g is a vector function and g(p)>=0 or g(p)<=0.

#2 Help Me ! » proof » 2006-04-07 06:09:44

razor
Replies: 2

we have function g,in Real numbers dimension m and value p (with p=(p1,...,pm)) is positive.
For at least one p,that g(p)>zero  or equal to zero or g(p)<zero or equal to zero,is true.Also,p*g(p)=0 for p positive.

Then,proof that g(p)=0.

#3 Help Me ! » minimum » 2006-03-14 08:44:50

razor
Replies: 1

We have the real  positive(only) numbers space of dimension two.
C={(x,y) belong to RxR and x+2*y<=2) and f(x,y)=min{x,y}.What is the minimum,x or y?

#4 Help Me ! » Help » 2006-03-05 10:54:30

razor
Replies: 1

We have the real  positive(only) numbers space of dimension n.We have also a relation of two members(sorry),continuous,absoletuly monotonic(only >),cursive,in this space.
Also x,y are arrays and x>y in this space and 0<a<1.
How can we proove that  a*x+(1-a)*y>y ?.   (*:  multiplication)

(G. Aliprantis, D. Brown and O. Burhinshaw, Existence and Optimality of Competitive Equilibrium, Springer-Verlag, 1990.)

sorry for my english.

#5 Puzzles and Games » Pentagram » 2006-02-25 13:43:58

razor
Replies: 7

we have a pentagram.How we can with two lines create nine not covertly triangles?

#6 Help Me ! » sequence » 2006-02-24 07:05:30

razor
Replies: 1

terms of sequence 10,2,1,9,6,...
what are the others terms?
do not exist other data.

this is a solution and why?
10,2,1,9,6,7,0,8,5,4,3

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