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## #1 Re: Help Me ! » logarithms... » 2005-11-11 09:44:08

ahh sry my fault but how? can you explain it pls

## #2 Re: Help Me ! » logarithms... » 2005-11-11 09:21:22

thanx alot, but in my book it says 3)=16 and 4)=1
any ideas, and also i forogot to mention that log6 2 means the base is 6..
thx!

thx alot guys

## #4 Help Me ! » logarithms... » 2005-11-11 05:58:10

pman
Replies: 5

hi!

``````1) lg(1-x)+lg(1+x)=lg0.75
2) 2 lgx=lg2 +lg18
3) 2 lgx - lg4 = lg(3x + 16)
4) log6 2 +log6 3``````

thanx for the help

## #5 Help Me ! » need explaination » 2005-11-10 16:17:01

pman
Replies: 3

hi can someone explain in detail how to solve this kind of problem please:

`````` 1)  7*4^x = 5*9^x

2)log3 3 + log9 1``````

you should use logarithms to solve it, thx!

## #6 Help Me ! » really need help!!! » 2005-11-04 14:22:49

pman
Replies: 1

hi!
i´ve got this problem i cant solve

`` ( (4x-x^2)/(9-x^2 ) ) /  ( (8-4x)/(3+x) )``

## #7 Re: Help Me ! » math problem » 2005-11-04 04:31:48

hey can someone fin a solution or not?

## #8 Re: Help Me ! » math problem » 2005-11-03 11:40:40

is there a solution??
btw is that text or a picture?
i really need this someone pls help i dont have a clue!

## #9 Re: Help Me ! » math problem » 2005-11-03 10:36:26

sorry i thought you could make a link like that

the problem is ofcourse this

( (4x-x^2) /(9-x^2 ) /  ( (8-4x)/(3+x) )