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This questions seems so simple, but I'm kind of stumped by the fact that it has factorials. I'm not sure how to go around solving it. >_<
Basically, it says,
Show that
There's also a bit before this question which tells me to
Prove that if f(r)=r!, then f(r+1)-f(r)=r x r!.
However, I'm not sure about this either. >_<
Please help me. Thank you in advance
Multiply through by r! for the first question and and see what happens.
For the second: f(r+1) - f(r) = (r+1)! - r! = (r+1)r! - r! = r![(r+1) - 1] = r!r
Last edited by Daniel123 (2008-10-22 04:24:56)
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Multiply through by r! for the first question and and see what happens.
For the second: f(r+1) - f(r) = (r+1)! - r! = (r+1)r! - r! = r![(r+1) - 1] = r!r
I never knew that you could take out a factor of r! from (r+1)!.
But I'm still not sure what to do for the first bit.
Where would that lead me?
I never knew that you could take out a factor of r! from (r+1)!.
(r+1)! = (r+1).(r).(r-1).(r-2)...3.2.1 = (r+1)r!
But I'm still not sure what to do for the first bit.
Where would that lead me?
You've not multiplied correctly. Anyway, I wouldn't really set it out like that - it was just to give you an idea.
Last edited by Daniel123 (2008-10-22 05:48:23)
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Oh dear. I'm still not getting this, I haven't done fractions with factorials in them. >_< Er... I might see my teacher because I think we've missed some important stuff out (as we're doing FP1 without having first completed C1 and C2 beforehand.)
If you rearrange that fraction in the order of (r-1)!r you will see it.
(r-1)! r = 1 x 2 x 3 x .....(r-1) x (r-1+1) = 1 x 2 x 3 x .....(r-1) x r = r!
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