You are not logged in.
I am trying to calculte the surface area of a toblerone shaped object but am stuck :
Length = 10cm
Height = 3cm
Width = 4 cm
Please help!
Last edited by blue44 (2008-09-14 03:34:37)
Offline
Is the shape something like this?
Offline
Hi Jane
Yes this is the shape I am struggling with!
Offline
The surface area is made of 5 shapes - two triangles at each and, and three rectangles around the sides.
The area of the triangle is easy to find since you are given the base length and height.
Using A = bh/2, the area of each triangle is 3*4/2 = 6.
The rectangles are a little trickier, since you need to work out their width first.
The rectangle on the bottom has a width of 4 (since the triangle has a base length of 4), and for the other two you need Pythagoras.
Splitting the triangle down the middle gets you a right-angled triangle with short lengths of 2 and 3.
Therefore, the hypotenuse must be √(2²+3²) = √13.
So there are two rectangles with a width of √13, which will have an area of 10√13, and one rectangle with a width of 4 which has an area of 40.
Adding it all up gives an overall surface area of 6+6+40+10√13+10√13 = 52+20√13 ≈ 124cm².
Why did the vector cross the road?
It wanted to be normal.
Offline
Thank you, thank you, thankyou! This answer was so clear and well explained
I had spent so much time trying to find the answer and nothing made sense to me before. Thank you!
Offline