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Matrix A=
5k 1
9 1
calculate (transpose(x)*A*x ) where x=
x1
x2
Hence
find the set of values for k where A is positive definite using your result of (transpose(x)*A*x ) for all non zero x in R^2
Last edited by mathshelpstudent8 (2008-05-13 21:23:59)
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Multiplying 3 matrices is just multiplying 2 matrices twice.
Start with, say, Ax.
Ax = (5k 1) (x1) = (5kx1 + x2)
( 9 1) (x2) (9x1 + x2)
Now you have Ax as a vector, so you can work out x*(Ax), a scalar.
A matrix is defined to be positive definite if x*Ax > 0, for any non-zero real vector x.
Therefore, once you have your scalar, you need to find what value of k will guarantee it to be positive, regardless of what x1 and x2 are (excluding when they're both 0).
Why did the vector cross the road?
It wanted to be normal.
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