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Im trying to do this initial-value problem in which I know what to do but I do get a step they do on the Solutions Manual.
Heres the problem
dy/dx=(x^2 - 1)/(x^2 + 1)
y(1) = (pi)/2
Now I know I have to take the integral of dy/dx but in order to take the integral in the Solutions Manual they rewrite dy/dx as:
dy/dx = 1 - (2/(x^2 + 1))
How does one go from the first dy/dx to the rewritten one?
Thanks.
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Why did the vector cross the road?
It wanted to be normal.
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