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#1 2007-11-10 00:22:38

JohnnyReinB
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Registered: 2007-10-08
Posts: 453

Contradictions

Sometimes, It is the subtle mistakes that make the biggest mistakes


Got any good contradicting equations? Maybe people could donate such, and others would try to find out what is wrong...

Let's start easy:





(this was in our exam, I thought it was pretty easy for us, until I asked my classmates what they answered...dizzy)

Last edited by JohnnyReinB (2007-11-10 00:51:28)


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#2 2007-11-10 00:36:03

luca-deltodesco
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Registered: 2006-05-05
Posts: 1,470

Re: Contradictions

for anyone that doesn't spot it. the first line states x < 0, so x is negative, at step 4, the equation is being divided by x, a negative number, so that sign has to change direction to 2x/x > x/x, which then leads to the right result of 2 > 1


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#3 2007-11-10 00:40:57

luca-deltodesco
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Registered: 2006-05-05
Posts: 1,470

Re: Contradictions

Heres an interesting one from wikipedia which cannot be done in the same way as yours to show its false.

for complex x:

Last edited by luca-deltodesco (2007-11-10 00:42:05)


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#4 2007-11-10 00:47:46

Jai Ganesh
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Registered: 2005-06-28
Posts: 45,956

Re: Contradictions

I remember one tricky question based on contradictions.

The question was, there's a person who who always speaks the truth. There's another who always lies. A stranger comes to the place where there are these two men. The question is, with only one question to ask any of the two, he should be able to tell who's the person who speaks the truth always and who's the liar.

The solution is a bit tricky. The stranger ought to ask a question 'What would the liar say if  asked him who's the liar'. If he's the liar, he'd point to himself. That is because, in reality, the liar would have pointed to the truth speaker. But since he doesn't speak the truth, he'd point himself. If he's the one who always speaks the truth, he'd have pointed the liar. Since he does not lie, now he'd point to the liar. Either way, the index finger would be aimed at the liar. This way, the liar can easily be found.

In reality, we come across many contradictory statements. He's a regular late-comer.
There was  a law and order failure in the city.
The best I have come across is he is consistently inconsistent. A classic oxymoron!
I know him, he's unpredictable is another.


It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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#5 2007-11-10 01:36:47

luca-deltodesco
Member
Registered: 2006-05-05
Posts: 1,470

Re: Contradictions

note quite johnny, its perfectly valid to only substitue into parts of the equation, the problem is something more ambiguous.


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#6 2007-11-10 03:31:41

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: Contradictions

Last edited by JaneFairfax (2007-11-10 03:33:23)

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#7 2007-11-18 21:57:01

JohnnyReinB
Member
Registered: 2007-10-08
Posts: 453

Re: Contradictions

Ok, so it's like this one:


  by dividing both sides by x

And, by substituting to the first equation, you get...

simplified, is
multiplying both sides by x...
finding the cube root...

So now, to check, substitute again...

simplified, is
Which is ,obviously, wrong...

Ok...right?

Last edited by JohnnyReinB (2007-11-18 21:57:30)


"There is not a difference between an in-law and an outlaw, except maybe that an outlaw is wanted" wink

Nisi Quam Primum, Nequequam

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#8 2007-11-19 00:43:39

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: Contradictions

Yep, it’s the same. That’s because in the the original equation, x is complex. Therefore, x should be a complex solution of x[sup]3[/sup] = −1, not x = −1. One must always be wary of such psychological pitfalls in mathematics. smile

Put it this way. You start with a quadratic equation, then you manipulate it and turn it into a cubic one. By doing so, you’ve introduced a stray solution to the equation – and it so happens that x = −1 is that stray solution. It’s like solving an equation involving surds (square roots): if you square both sides to get rid of the square roots, you introduce extra solutions into your equation; hence you need to substitute the solutions you’ve found back into the original equation to see which ones don’t fit.

Last edited by JaneFairfax (2007-11-19 00:49:47)

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#9 2007-11-22 17:18:56

JohnnyReinB
Member
Registered: 2007-10-08
Posts: 453

Re: Contradictions

So, how do you solve these equations?


"There is not a difference between an in-law and an outlaw, except maybe that an outlaw is wanted" wink

Nisi Quam Primum, Nequequam

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