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#1 2021-04-18 06:42:01

mathland
Member
Registered: 2021-03-25
Posts: 444

Swimming Pool

Water is leaking out of a swimming pool that measures 20 ft by 40 ft by 6 ft. The amount of water in the pool at a time t is W(t) = 35,000 − 20t^2 gallons, where t equals the number of hours since the pool was last filled. At what rate is the
water leaking when t = 2h?

NOTE: I am not seeking the answer but the set up only. I will do the math work.


Thank you.

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#2 2021-04-18 22:17:05

Bob
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Registered: 2010-06-20
Posts: 10,053

Re: Swimming Pool

Find dW/dt and then put in the given t value.

B


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#3 2021-04-19 08:48:49

mathland
Member
Registered: 2021-03-25
Posts: 444

Re: Swimming Pool

Bob wrote:

Find dW/dt and then put in the given t value.

B


Hello Bob.

Let me see.

dW/dt = d/dt [35,000 − 20t^2]

dW/dt = -40t

What do I do with dW/dt?

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#4 2021-04-19 14:02:29

Mathegocart
Member
Registered: 2012-04-29
Posts: 2,226

Re: Swimming Pool

mathland wrote:
Bob wrote:

Find dW/dt and then put in the given t value.

B


Hello Bob.

Let me see.

dW/dt = d/dt [35,000 − 20t^2]

dW/dt = -40t

What do I do with dW/dt?

Plug t=2 hours into dW/dt as the problem tells you to.


The integral of hope is reality.
May bobbym have a wonderful time in the pearly gates of heaven.
He will be sorely missed.

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#5 2021-04-19 15:25:31

mathland
Member
Registered: 2021-03-25
Posts: 444

Re: Swimming Pool

Mathegocart wrote:
mathland wrote:
Bob wrote:

Find dW/dt and then put in the given t value.

B


Hello Bob.

Let me see.

dW/dt = d/dt [35,000 − 20t^2]

dW/dt = -40t

What do I do with dW/dt?

Plug t=2 hours into dW/dt as the problem tells you to.

Ok. Very easy to do when someone explains what is going on.

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