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Hi, my first post, and i need help with some applications of calculus to physics
A tank contains 100 litres of brine whose concentration is 3 grams/litres. Three litres of brine whose concentration is 2 grams/litre flow into the tank each minute and at the same time 3 litres of mixture flow out each minute.
Show that the quantity of salt, Q gram, in the tank at any time t is given by:
Q = 200 + 100e[sup]-0.03t[/sup]
i have managed to get Q = 200 - 100e[sup]-0.03t[/sup]
and cannot figure out why the minus is there, i have included the pdf of the working i have done so far, any help appreciated
thanks
jacs
Last edited by jacs (2006-01-16 02:05:35)
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You use a different method for solving differential equations than I'm used to, and quite an awkward one at that. See if you can follow this, and if you want, I can try to find the error in your steps.
Integrate both sides
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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Nice work, Ricky!
Show that the quantity of salt, Q gram, in the tank at any time t is given by:
Q = 200 + 100e[sup]-0.03t[/sup]
And, of course, the 100e[sup]-0.03t[/sup] term decreases with t, so it should be added.
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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thank you thankyou thankyou I see it now.... i had the negative log and so cheated assuming that the 3Q was 300 instead of 900 (which i secretly knew was wrong...lol....but coudnt get rid of negative log so sort fudged the results)
what i needed was just the clever maniplutaion of the minus...ohhh soo easy now i see
thanks
jacs
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