You are not logged in.
Pages: 1
Hi, I need help in finding vertical asymptote in particular question:
f(x)= 2x²-5/x+2, x≠ -2
a. Show that x= -2 is a verical asymptote.
Please explain how to find it..
Thank you
Hi, I need help in finding vertical asymptote in particular question:
f(x)= 2x²-5/x+2, x≠ -2
a. Show that x= -2 is a verical asymptote.Please explain how to find it..
Thank you
Hi Makaros,
vertical asymptotes appear when the denominator of a fraction = 0
so x+2=0
x=-2
is your asymptote:)
"If your going through hell, keep going."
Offline
Hi Makaros;
glenn101 has correctly understood your meaning but you should put a parentheses around that denominator.
As written f(x)= 2x²-5/x+2 is
f(x)= 2x²-5/(x+2) is
what you want to say.
Last edited by bobbym (2009-07-18 19:03:08)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
In a book it says I have to use limit to find it... How to find Vertical asymptote using a limit?
Thanks)
Pages: 1