# Math Is Fun Forum

Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫  π  -¹ ² ³ °

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## #1 2006-04-22 18:32:15

Jai Ganesh
Registered: 2005-06-28
Posts: 47,827

### Set Theory

Set:- A well defined collection of objects is called a set.

There is no repetition of elements in a set, each element appears only once.

Elements of a set:- The objects in a set are called its members or elements.

If an element a is prsent in setA, it is denoted by

If the element a is not present in set A, it is denoted by

Description of a set

I. Roster mehod:-
In this method, a list of all the objects of the set is made and they are put within braces.

Example 1:- If A is the set of the first eight prime numbers,
A={2, 3, 5, 7, 11, 13, 17, 19}

Example 2:- If B is the set of all the counting numbers between 20 and 30, B={21, 22, 23, 24, 25, 26, 27, 28, 29}

II. Set Builder form:-
In this method, the properties common to all the elemnts of the set are listed.
It is written in the form{x:x has properties P}

Example 1:- If B={3,5,7,9,11}, it is written as
B={x:x=2n+1 where n∈N, n<6} or
B={x|x=2n+1 where n∈N, n<6}

Singleton set:- A set consisting of a single elements is called a singleton set.
Example :- A={2} or A={x:x is an even prime number}

Empty set:- A set which has no elements is called an empty set. It is represented by {} or

Finite and Infinite sets:- A finite set is one in which the number of elements is finite.
Example:- A={x:x is a multiple of 5, x<1,000,000,000}

An infinite set is one in which the number of elements is not finite.
Examples:- Set of all points on the arc of a circle, Set of all concentric circles with a given centre,
{x|x∈Q, 0<x<1} (Q is the set of Rational numbers).
Equal sets:- Two sets A and B are equal if every element of set A is in set B and everyelement of set B is in set A. It is denoted by
A=B.

Cardinal Number of a set:-The number of (distinct)elements in a set is called the Cardinal number of the set.
If A is the set, n(A) is the caridanl number of set A.

Example:- If A={0,1,2,3,4,5,6,7,8,9}, n(A)=10

Equivalent sets:-Two sets are said to be equivalent if n(A)=n(B), that is, if their cardinal numbers are equal.

Remark:- Equal sets are always equivalent but equivalent sets are not always equal.
Example:-
if A={1,2,3,4,5}, B={a,b,c,d,e}
A and B are equivalent sets because n(A)=n(B)=5, but A and B are not equal sets.

Subset:- Let A and B be two sets given in such a way that every element of A is in B, then it is said that A is a subset of B, written as

Superset:-If A is a subset of B, then B is a superset of A, denoted by

Proper subset:- If A is a subset of B and set A is not equal to set B, then A is called a proper subset of B, denoted by

Example, if A={1,2,3}, B={1,2,3,4,5,6,7}, then

Comparable sets:- Two sets A and B are comparable either if
A is a subset of B or B is a subset of A.

Properties of Subsets:-

1. {}, the empty set, is a subset of all sets.

2. Every set is a subset of itself.

3. The number of all subsets of a set containing n elements is

4. The number of all proper subsets of a set containing n elements is

5. The set of all subsets of a given set A is called the Power set of set A, denoted by P(A).
If A has n elements, P(A) has

elements.

Operation on sets

Union of sets:- The union of two sets A and B is the set of all eleements in A or in B or in both A and B. It is denoted by

Example:- if A={0,2,4,6,8,10} and B={1,2,3,4,5},

Intersection of sets:- The intersection of two sets A and B is the set of elements common in A and B.

It is denoted by

If A={0,2,4,6,8,10} and B={1,2,3,4,5},

Difference of sets:-

The difference of two sets A and B is defined as the elements present in set A not present in set B.

It is denoted by A-B.

If A={0,2,4,6,8,10} and B={1,2,3,4,5},

A-B={0,6,8,10} and B-A={1,3,5}

It should be remembered that

Symmetric Difference of sets:- The symmetric difference of two sets A and B is defined as

Symmetric difference is commutative.

If A={0,2,4,6,8,10) and B={1,2,3,4,5},
A-B={0,6,8,10}, B-A={1,3,5}

Universal Set:- A set which is a superset of all the given sets, denoted by U, is known as the Superset.

Complement of a Set:-
If set A is the subset of Universal set U, then the complement of A, denoted by

is the set of all the elements in the Universal set not in A.

Example:-
if U={a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z} and
A={a,e,i,o,u}, then

Important results on Complements

Laws of Operations

It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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## #2 2006-04-22 19:24:45

Jai Ganesh
Registered: 2005-06-28
Posts: 47,827

### Re: Set Theory

Commutative Laws:-

Associative Laws:-

Distributive Laws:-

De Morgan's Laws:-

It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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## #3 2006-04-22 23:54:17

Jai Ganesh
Registered: 2005-06-28
Posts: 47,827

### Re: Set Theory

Number of elements in a set

Example

Let

As per the formula,

Therefore, LHS=RHS.

It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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## #4 2006-04-23 00:53:41

Jai Ganesh
Registered: 2005-06-28
Posts: 47,827

### Re: Set Theory

Some Important Results

It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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## #5 2006-04-23 00:58:09

Jai Ganesh
Registered: 2005-06-28
Posts: 47,827

### Re: Set Theory

Cartesian Product

The Cartesian Product of two sets A and B is defined to be the set of all ordered pairs with the first element in A and the second element in B. The Cartesian Product is denoted by

Example:- A={1,2,3}, B={a,b}

Imortant Results of Cartesian products

If A or B or both are infinite sets, A X B is also an infinite set.

It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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## #6 2006-11-24 02:28:50

knvsp123
Member
Registered: 2006-11-24
Posts: 1

### Re: Set Theory

how can we say minimum no of elements of AUB IF N(A)=8 AND N(B)=5

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## #7 2007-02-21 12:20:49

Sekky
Member
Registered: 2007-01-12
Posts: 181

### Re: Set Theory

you said: "

denotes an element is not in the set"

this is wrong, the correct notation is

Last edited by Sekky (2007-02-21 12:28:13)

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## #8 2007-02-21 16:45:33

Jai Ganesh
Registered: 2005-06-28
Posts: 47,827

### Re: Set Theory

Hi Sekky,
Welcome to the forum!
Thanks for the post!
I do agree, the symbol you have given is used to denote 'does not belong to'. But the one I had given is also used.
Thanks again.

It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Online

## #9 2007-02-21 20:46:08

Sekky
Member
Registered: 2007-01-12
Posts: 181

### Re: Set Theory

ganesh wrote:

Hi Sekky,
Welcome to the forum!
Thanks for the post!
I do agree, the symbol you have given is used to denote 'does not belong to'. But the one I had given is also used.
Thanks again.

No, it isn't, it's used to denote containment, not lack thereof. It's simply back to front, equally as every single other binary relation can be written back to front, as in subset containment or have you ever heard of < and >? The symbol means the same, but the relation is reflexed.

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## #10 2007-02-22 05:16:55

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

### Re: Set Theory

Sekky, this is a big world with many, many, mathematicians.  Is it really that much of a surprise that two different mathematicians don't use exactly the same symbols?

Symbols are arbitrary.  They can mean whatever you want them to.  There are standards, but different people may conform to different standards.

Actually this list should really be in the algebra formulas thread, since a set is just a degenerate algebra.

Can you please define "degenerate algebra"?  Wikipedia, MathWorld, and myself have no idea what you mean when you say that.  Also, if you're going to go with that notion, then every thread in the formula section should be put into Sets, as sets are pretty much the basis of all math.

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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## #11 2007-02-22 05:29:33

Sekky
Member
Registered: 2007-01-12
Posts: 181

### Re: Set Theory

Ricky wrote:

Sekky, this is a big world with many, many, mathematicians.  Is it really that much of a surprise that two different mathematicians don't use exactly the same symbols?

Symbols are arbitrary.  They can mean whatever you want them to.  There are standards, but different people may conform to different standards.

Actually this list should really be in the algebra formulas thread, since a set is just a degenerate algebra.

Can you please define "degenerate algebra"?  Wikipedia, MathWorld, and myself have no idea what you mean when you say that.  Also, if you're going to go with that notion, then every thread in the formula section should be put into Sets, as sets are pretty much the basis of all math.

He's using the same symbol to denote both the relation and the opposite relation, it makes no sense. The subset relation means the same back to front providing the relatives are switched, as does the less than symbol, as do any mathematical relations.

Last edited by Sekky (2024-06-24 09:13:05)

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## #12 2007-02-22 16:45:29

Jai Ganesh
Registered: 2005-06-28
Posts: 47,827

### Re: Set Theory

Sekky,
The formulas section is intended to help the members and all the students in general.
The beginners identify set theory as a separate branch, when these threads werte created, the idea was to put all formulas useful to students. Whether a thread was a subset of one or superset was not a point of concern.
Ricky and me were posting the formulas, and we wanted to create a databse. I think we have done fairly well in our endeavor!

It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Online

## #13 2007-02-22 17:05:23

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

### Re: Set Theory

Morphisms, Operators, Relations ect, are not constructed from set algebras

A morphism is a mapping.  A mapping is simply a special subset of AxB, where the mapping would be from A to B.

An operator is a mapping from AxA->A, which is in turn a subset of (AxA)xA.

A relation is again a subset of AxB.

He's using the same symbol to denote both the relation and the opposite relation, it makes no sense.

That's like saying:

and

Are the same symbol.  I mean, they are just flipped around, right?

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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## #14 2007-02-23 00:24:00

MathsIsFun
Registered: 2005-01-21
Posts: 7,713

### Re: Set Theory

In my experience there are alternative notations (which often lead to confusion, but that is how the world is).

Perhaps we could include a note to that effect?

And then, sorry to say, we will need to clean up the discussion according to http://www.mathsisfun.com/forum/viewtopic.php?id=3284

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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## #15 2007-02-23 03:29:56

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

### Re: Set Theory

Those are binary operators, which are commutative and therefore denoted such that it makes no different if you flip them horizontally because the operands won't need to change. we're talking about non-symmetric relations here.

Whats a binary operator?  Intersection and union or inclusion?  Cause neither are.  A binary operator is a mapping from AxA to A.

And then, sorry to say, we will need to clean up the discussion according to http://www.mathsisfun.com/forum/viewtopic.php?id=3284

I will be doing so once this is resolved.

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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## #16 2007-02-23 12:18:58

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

### Re: Set Theory

Given any set, both intersection and union map P|A| x P|A| -> P|A|

Union an intersection each take two different sets.  Not the same set, though they can be.

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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## #17 2007-02-23 12:23:28

Sekky
Member
Registered: 2007-01-12
Posts: 181

### Re: Set Theory

Ricky wrote:

Given any set, both intersection and union map P|A| x P|A| -> P|A|

Union an intersection each take two different sets.  Not the same set, though they can be.

So you're saying any binary operator can only ever take the same element for it's operands? 2 + 3 = 5 last time I heard.

The mapping maps all elements of the set cart set to another element of the set, and they will forever be included in the power set of any given set, thusly.

Let A = {1,2,3}

P|A| = {{},{1},{2},{3},{1,2},{1,3},{2,3},{1,2,3}}

Now take the union and intersection of all possible cartesian tuples of the power set, and the yield will ALWAYS be an element of the power set, hence P|A| x P|A| -> P|A|

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## #18 2007-02-23 12:56:27

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

### Re: Set Theory

So you're saying any binary operator can only ever take the same element for it's operands? 2 + 3 = 5 last time I heard.

No, but the elements must belong to the same set.  In other words, the integers.

Let A = {1,2,3}

P|A| = {{},{1},{2},{3},{1,2},{1,3},{2,3},{1,2,3}}

Now take the union and intersection of all possible cartesian tuples of the power set, and the yield will ALWAYS be an element of the power set, hence P|A| x P|A| -> P|A|

Yes, but this is restricting the definition of union because I can take:

B = {4, 5, 6}

And do A U B.

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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## #19 2007-02-23 13:06:49

Sekky
Member
Registered: 2007-01-12
Posts: 181

### Re: Set Theory

hence A and B are both elements of P|{1,2,3,4,5,6}| and no generality is lost, Z x Z -> Z necessarily for some Z = P|{1,2,3,4,5,6}|

Operators are associated with algebras to form more composite algebras, if I take a set, I can find an operator to form an algebra. Likewise if I find an operator and element I wish to perform, I can find a set containing them such that the operator will hold an algebra.

Last edited by Sekky (2007-02-23 13:10:43)

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## #20 2007-02-23 13:15:40

Sekky
Member
Registered: 2007-01-12
Posts: 181

### Re: Set Theory

or better, why not just consider the power set of the universal set under both operators, and I believe that forms a boolean lattice.

Well, any set under both operators will be a boolean lattice, I believe, unless you can think of an axiom that fails.

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## #21 2007-02-23 13:18:27

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

### Re: Set Theory

hence A and B are both elements of P|{1,2,3,4,5,6}|

Ah, I see.  So now we're defining union by taking the union of two sets?  And you don't see the problem in that?

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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## #22 2007-02-23 13:32:17

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

### Re: Set Theory

And there in lies the problem.  You are operating under what is called (I swear, this is the actual term, I'm not trying to be insulting), "naive set theory".  It is the concept that any collection can be a set.  Naive set theory is called so because it is, well, naive.  It leads to contradictions and paradoxes.

On the other hand, I am going off of ZF set theory, which is the just about the standard when it comes to set theory in mathematics (although there are others).  In ZF set theory, you can't just claim something is a set.  The set must be constructed through the use of existing sets.  The only set that is guaranteed to exist is the null set (which I will be denoting θ simply because of laziness).  But through precise axioms, we can take the null set and form sets such as {θ} and {{θ}} or {θ, {{θ}}}.  In ZF set theory, the Axiom of Union is used to define what we typically think of when we see union (though said in a completely different form).

So you need union to state that your set {1, 2, 3, 4, 5, 6} exists before you can ever even talk about it being a set.  And this is the reason why we can never have union be an operator.  Because the sets need to exist before we can call it an operator, but we need union to exist before we can say the sets exist.

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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## #23 2007-02-23 16:45:14

MathsIsFun
Registered: 2005-01-21
Posts: 7,713

### Re: Set Theory

Guys, this is such a great discussion, but it is in the Formulas section, so due for deletion at some point!

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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## #24 2007-02-23 18:32:13

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

### Re: Set Theory

Sekky, we're starting to beat around the bush here.  Please come up with a binary operator definition for the union of two (possibly different) sets.

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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## #25 2007-02-26 04:05:58

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

### Re: Set Theory

I'm sorry, but that is not a binary operation.  A binary operation is a mapping from AxA to A.

"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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