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A wire of length x is bent into the shape of a circle.
A. Express the circumference C of the circle as a function of x.
B. Express the area A of the circle as a function of x.
Let me see.
Part A
Circumference of circle = pi•d, where d is diameter, which can also be expressed as 2r•pi, where r = radius of circle. We want C(x).
Let C = length x
x = 2r•pi
Solve for r.
x/2•pi = r....plug into circumference of circle formula.
C = 2r•pi
We want C(x).
C(x) = 2(x/2•pi)(pi)
C(x) = x
You say?
Part B
From part A, I know that r = x/2•pi.
We want A(x).
Area of circle = pi•r^2.
A(x) = pi(x/2•pi)^2
A(x) = pi(x^2/4•pi^2)
A(x) = x^2/(4•pi)
You say?
The greatest truth about the Rapture is not its timing but it's reality.
Dr. David Jeremiah
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Both parts good.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Both parts good.
Bob
I don't know how I got this right. I greatly struggle with forming mathematical models.
The greatest truth about the Rapture is not its timing but it's reality.
Dr. David Jeremiah
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