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#1 2024-04-27 07:47:44

mathxyz
Member
From: Brooklyn, NY
Registered: 2024-02-24
Posts: 877

Wire of Length x

A wire of length x is bent into the shape of a circle.


A. Express the circumference C of the circle as a function of x.


B. Express the area A of the circle as a function of x.


Let me see.


Part A


Circumference of circle = pi•d, where d is diameter, which can also be expressed as 2r•pi, where r = radius of circle. We want C(x).



Let C = length x


x = 2r•pi


Solve for r.


x/2•pi = r....plug into circumference of circle formula.


C = 2r•pi


We want C(x).


C(x) = 2(x/2•pi)(pi)


C(x) = x


You say?


Part B


From part A, I know that r = x/2•pi.


We want A(x).


Area of circle = pi•r^2.


A(x) = pi(x/2•pi)^2


A(x) = pi(x^2/4•pi^2)


A(x) = x^2/(4•pi)



You say?


The greatest truth about the Rapture is not its timing but it's reality.

Dr. David Jeremiah

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#2 2024-04-27 19:41:26

Bob
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Registered: 2010-06-20
Posts: 10,374

Re: Wire of Length x

Both parts good.

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#3 2024-04-28 01:23:08

mathxyz
Member
From: Brooklyn, NY
Registered: 2024-02-24
Posts: 877

Re: Wire of Length x

Bob wrote:

Both parts good.

Bob

I don't know how I got this right. I greatly struggle with forming mathematical models.


The greatest truth about the Rapture is not its timing but it's reality.

Dr. David Jeremiah

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