Analyze h(x)

nycguitarguy · 2024-03-16 01:37:43

Given h(x) = (-32x^2)/(130)^2, do A to C.

A. Find x when h(x) = 0.

The set up us this:

0 = (-32x^2)/(130)^2

You say?

B. Find domain of h algebraically

To find domain, I must repeat my work for part A.

You say?

C. Find range of h algebraically

How is this done algebraically?

D. Find all intercepts

To find the x-intercept(s), I must let h(x) = 0.

Yes?

To find the y-,intercept(s), I must let x = 0.

Yes?

What do you really say?

Bob · 2024-03-16 01:59:08

A ok.

Have a look at the graph for the rest.

Bob

nycguitarguy · 2024-03-16 11:58:54

Bob wrote:

A ok.
Have a look at the graph for the rest.
Bob

I will use a graph.

KerimF · 2024-03-17 00:40:06

Bob wrote:

A ok.
Bob

Ok?!
I see him just replacing h(x) with a zero:
0 = (-32x^2)/(130)^2

I guess he needs to go on a bit further to deduce the value of x.

KerimF · 2024-03-17 00:43:21

FelizNYC wrote:

Given h(x) = (-32x^2)/(130)^2, do A to C.
B. Find domain of h algebraically

I expected to read instead:
B. Find domain of x algebraically

KerimF · 2024-03-17 00:45:01

FelizNYC wrote:

Given h(x) = (-32x^2)/(130)^2, do A to C.
D. Find all intercepts
To find the x-intercept(s), I must let h(x) = 0.
Yes?
To find the y-,intercept(s), I must let x = 0.
Yes?

Both correct.

Last edited by KerimF (2024-03-17 00:45:33)

nycguitarguy · 2024-03-17 01:09:35

KerimF wrote:

FelizNYC wrote:
Given h(x) = (-32x^2)/(130)^2, do A to C.
D. Find all intercepts
To find the x-intercept(s), I must let h(x) = 0.
Yes?
To find the y-,intercept(s), I must let x = 0.
Yes?
Both correct.

Perfect. I can take it from here.

Math Is Fun Forum

#1 2024-03-16 01:37:43

Analyze h(x)

#2 2024-03-16 01:59:08

Re: Analyze h(x)

#3 2024-03-16 11:58:54

Re: Analyze h(x)

#4 2024-03-17 00:40:06

Re: Analyze h(x)

#5 2024-03-17 00:43:21

Re: Analyze h(x)

#6 2024-03-17 00:45:01

Re: Analyze h(x)

#7 2024-03-17 01:09:35

Re: Analyze h(x)

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