Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2008-11-30 15:45:30

mathwizardhatshoe
Guest

Simple Integral?

i need to use the integral test to find whether or not a series is convergent or divergent

∫(1/x²) dx

for this i only need to find wether or not they are convergent or divergent

they are both series from n=1 to n=∞


∑ (  (n+1) / (2n+3)  )



∑ (  (sin²n) / (n²)  )



any help? steps please i am having trouble with this stuff smile thanks

#2 2008-11-30 18:06:45

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: Simple Integral?

For the first, just use the comparison test.  For the 2nd, use the comparison and then the integral test.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

Offline

Board footer

Powered by FluxBB