Math Is Fun Forum

This can be solved using calculus but to keep things easier, I just have a way: calculate everything from both LHS and RHS.
LHS = 1 + 1/16 + 1/81 + 1/256...... (notice that's decreasing rapidly when we increase n. So few numbers might give correct result. I'll use only 8 terms:)
       = 1 + 0.0625 + 0.0123 + 0.00390625 + 0.0016 + 0.0007716049 + 0.000416493 + 0.0002441406
       = 1.0815
RHS = 1.082

They are found to be equal up to 3 decimals and if you want more accuracy use more digits.

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Hi guys!

In Nepal, we are mainly taught 3 ways of solving quadratic equations: product sum method, completing square method and the formula method. You can read the whole chapter here: https://lms.neemaacademy.com/course/2095/School-Mathematics-Grade-10/component/ynPP0L

In the product sum method, which only works for integers, we do the steps:

For any equation like:

, we do:
- Multiply a with c to make ac
- Check whether it's sum or difference, if c > 0, it's sum else it's difference
- Find two numbers whose sum or difference is b and product is ac
- Once you have the numbers, keep them instead of b in the equation.

For example:

Here, ac = 6*(-10) = -60; use difference
The numbers whose product is 60 and difference is 11 are: 15 and 4.

Hence (2x+5) and (3x-2) are the solutions.

Hi,

Yes. Here's more from my Math's Book:

Hi,

Hi,
Thanks

Hi,

It's tough to solve this one but I'm trying:

Hi,

Hi,

Was abit tough one!

Hi Bob,
I was at school. Just came back. I turned on my laptop and I got that.

Hi,