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#1 Help Me ! » 2^3687 » 2009-09-17 22:43:44
- lashko
- Replies: 2
What are the three last digits of 2^3687??? 
can anyone explain the way how to solve this kind of problem?
Thanks a lot
#2 Re: Help Me ! » Limit » 2009-08-14 06:33:39
No L'Hopital does not apply. Ive thought about it
#3 Help Me ! » Sum of n-th degrees » 2009-08-14 06:19:48
- lashko
- Replies: 5
Hi everyone
Look, we know how to calculate ∑i , ∑(i^2) , ∑(i^3) when i is any positive integer from 1 to n and we can proove them by arithmetic sequence rules or induction, but, can we find a general formula for ∑(i^4)?
#4 Re: Help Me ! » Limit » 2009-08-14 05:59:21
Thanks guys you are right thats 1/2
#5 Help Me ! » Limit » 2009-08-13 10:35:35
- lashko
- Replies: 6
\lim_{x\to infinity} \, \sqrt{x^2+x}-x
#6 Re: Help Me ! » proof of the sum of squares » 2009-08-13 10:29:02
24[(n-1)²] + 2 = (2n-1)³ - (2n-3)³
24[(n)²] + 2 = (2n+1)³ - (2n-1)³
how did u get those equalities?
Thanks
#7 Re: Help Me ! » proof of the sum of squares » 2009-08-13 10:26:56
James wrote:
This is the text i want to quote.
#8 Re: Help Me ! » Related Rates » 2009-08-13 09:10:53
its too easy. You have to derivate the Pitagora equation with respect to time t and thats all.
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