Last edited by tony123 (2008-01-25 09:08:58)
Ya está resuelta en aquél foro. (I'm not gonna post the URL for not makin' SPAM.)
Tony: you should be patient, post your problems in one forum first, if you see that it's not solved, try with another ones.
let sinx=t for all x in [0,pi/2],then we got cosx=sqrt(1-x^2).so,(sinx)^25/[(sinx)^25+(cosx)^25]=t^25/[t^25+(\sqrt (1-x^2))]25=f(t).we can get the extreme values of f(t) as follows:
2.find t such that f'(t)=0;for example t1,t2;
3.f(t1),f(t2) is the maxium and inum
4.estimate the integral by the extreme value.
The 25's look scary but it isn't actually that difficult to show that
Last edited by sce1912 (2008-10-11 03:26:51)