You are not logged in.
Pages: 1
A hemisphere bowl of radius 12cm is initially full of water. Water runs out of a small hole at the bottom of the bowl at a rate of 48pi cm^3 s^-1. When the depth of the water is x cm , show that the depth is decreasing at a rate of 48/[x(24-x)] cm s^-1
Also, find the rate at which the depth is decreasing when
a) The bowl is full.
b)The depth is 6cm.
Another question is in this picture

Thanks in advance! Really urgent ![]()
Last edited by ose90 (2008-09-20 17:00:49)
Offline
imagine the right side of a semi-circle in 2D displaced vertically so the bottom rests at origin, it would have equation
rotating the region formed by right hand side's integral to a height 'h' around y axis gives the volume of hemisphere to a certain depth
Since we are looking for derivitive we don't need to evaluate this (although i think it's interesting to do anyways :P) i'm simply showing it to verify my next step of writing:
where x is the depth as in your question (not my first equation), and i've subbed the value for the radius in.the bowl is full; x = 12cm, dx/dt = 1/3 cms-¹
depth is 6cm, x = 6cm, dx/dt = 4/9 cms-¹
Last edited by luca-deltodesco (2008-09-20 20:24:16)
The Beginning Of All Things To End.
The End Of All Things To Come.
Offline
Thanks for your elaborated explanation. I have understood it in a more detailed way,thanks!
Would you mind helping me with the 2nd question?
REgards
Offline
Thanks you very much, glad to inform you that I have solved both questions.
Regards,
Frank
Offline
Pages: 1