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#1 2008-07-30 06:20:04

kwinrow
Member
Registered: 2008-07-30
Posts: 11

i have a question for this problem

Consider two tones with frequencies of 220 and 223 Hz and pressures P1=.005sin440(pie)t and P2=.005sin446(pie)t, respectively. Graph the pressure P= P1+P2 felt by an eardrum over the 1-sec interval [.15,1.15]. How many beats are there in 1 sec?

my work:

am I goin about this right?

P=.005sin(440pit)+.005sin(446pit)
P=.01sin(886pit)

now is this ready to graph in the interval [.15,1.15]?

or is there another step i need to do?

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#2 2008-07-30 07:05:35

ZHero
Real Member
Registered: 2008-06-08
Posts: 1,889

Re: i have a question for this problem

That's not right!
It should be..



now, you can use the formula

Last edited by ZHero (2008-07-30 07:15:05)


If two or more thoughts intersect, there has to be a point!

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#3 2008-07-30 07:13:07

kwinrow
Member
Registered: 2008-07-30
Posts: 11

Re: i have a question for this problem

ok so its:

0.005[sin(440pit)+sin(446pit)]=2sin(440+446/2)cos(440-446/2)?

then after this i get all terms to one side right? then graph?

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#4 2008-07-30 07:22:34

ZHero
Real Member
Registered: 2008-06-08
Posts: 1,889

Re: i have a question for this problem

You'll get..


now put the values of t in the range (0.15, 1.15) and find respective values of P and plot the graph accordingly...

Last edited by ZHero (2008-07-30 07:24:18)


If two or more thoughts intersect, there has to be a point!

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#5 2008-07-30 07:58:12

kwinrow
Member
Registered: 2008-07-30
Posts: 11

Re: i have a question for this problem

so if i decide to plug in .44 as x i should get one single value right?

then using the order pair plot the dot?

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#6 2008-07-30 09:29:45

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: i have a question for this problem

ZHero wrote:

tiny typo correction:
423 should be 443  and   23 should be -3    because -6/2 is -3.
   (sorry to be a pest)
(and don't forget the doubling or times 2 in that cool formula also)

P = 0.01 sin blah-blah  cos blah-blah

Last edited by John E. Franklin (2008-07-30 09:32:48)


igloo myrtilles fourmis

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#7 2008-07-31 01:14:18

kwinrow
Member
Registered: 2008-07-30
Posts: 11

Re: i have a question for this problem

I have no idea how to finish this problem I am stuck on this step:

P=0.01(sin(443pit)cos(-3pit))

how do i finish this?when i graph it on the calculator i get nothing

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#8 2008-07-31 04:10:19

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: i have a question for this problem

Well, the -3 can also be +3 or just 3 due to the nature of the cosine.
And I don't have a graphing calculator, but try this instead and
make sure you are in radians, not degrees.

y = 0.01*sin(443*pi*x)*cos(3*pi*x)

If your calculator is in degrees, then replace the pi's with 180's like this:

y = 0.01*sin(443*180*x)*cos(3*180*x)

Also you won't be able to see the graph because it is too short,
you have to zoom in or make the equation 100 times taller like this:

y = 100*0.01*sin(443*180*x)*cos(3*180*x)      (if in degrees use 180 for pi)

y = 100*0.01*sin(443*pi*x)*cos(3*pi*x)     (if in radians, use pi)


igloo myrtilles fourmis

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#9 2008-07-31 08:43:15

kwinrow
Member
Registered: 2008-07-30
Posts: 11

Re: i have a question for this problem

thank you so much

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