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Consider two tones with frequencies of 220 and 223 Hz and pressures P1=.005sin440(pie)t and P2=.005sin446(pie)t, respectively. Graph the pressure P= P1+P2 felt by an eardrum over the 1-sec interval [.15,1.15]. How many beats are there in 1 sec?
my work:
am I goin about this right?
P=.005sin(440pit)+.005sin(446pit)
P=.01sin(886pit)
now is this ready to graph in the interval [.15,1.15]?
or is there another step i need to do?
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That's not right!
It should be..
now, you can use the formula
Last edited by ZHero (2008-07-30 07:15:05)
If two or more thoughts intersect, there has to be a point!
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ok so its:
0.005[sin(440pit)+sin(446pit)]=2sin(440+446/2)cos(440-446/2)?
then after this i get all terms to one side right? then graph?
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You'll get..
Last edited by ZHero (2008-07-30 07:24:18)
If two or more thoughts intersect, there has to be a point!
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so if i decide to plug in .44 as x i should get one single value right?
then using the order pair plot the dot?
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tiny typo correction:
423 should be 443 and 23 should be -3 because -6/2 is -3.
(sorry to be a pest)
(and don't forget the doubling or times 2 in that cool formula also)
P = 0.01 sin blah-blah cos blah-blah
Last edited by John E. Franklin (2008-07-30 09:32:48)
igloo myrtilles fourmis
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I have no idea how to finish this problem I am stuck on this step:
P=0.01(sin(443pit)cos(-3pit))
how do i finish this?when i graph it on the calculator i get nothing
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Well, the -3 can also be +3 or just 3 due to the nature of the cosine.
And I don't have a graphing calculator, but try this instead and
make sure you are in radians, not degrees.
y = 0.01*sin(443*pi*x)*cos(3*pi*x)
If your calculator is in degrees, then replace the pi's with 180's like this:
y = 0.01*sin(443*180*x)*cos(3*180*x)
Also you won't be able to see the graph because it is too short,
you have to zoom in or make the equation 100 times taller like this:
y = 100*0.01*sin(443*180*x)*cos(3*180*x) (if in degrees use 180 for pi)
y = 100*0.01*sin(443*pi*x)*cos(3*pi*x) (if in radians, use pi)
igloo myrtilles fourmis
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thank you so much
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