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**tony123****Member**- Registered: 2007-08-03
- Posts: 189

Without use of any calculator, determine

*Last edited by tony123 (2008-07-18 09:48:53)*

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**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

, , and all satisfy the equation . Try and play around with that.

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**tony123****Member**- Registered: 2007-08-03
- Posts: 189

but from where you get these

JaneFairfax wrote:

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**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

Never mind, forget what I wrote above. I was being naughty and used a calculator.

But I got it now. Heres how.

By considering the sum of the complex roots of

, you haveBut

.Now

Note that

. HenceAnd

. And there you have it.*Last edited by JaneFairfax (2008-07-25 01:27:41)*

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**ZHero****Real Member**- Registered: 2008-06-08
- Posts: 1,889

Kya baat hai!!?

That's a nice smiley too by the way!

If two or more thoughts intersect, there has to be a point!

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**John E. Franklin****Member**- Registered: 2005-08-29
- Posts: 3,588

Jane, I don't get where the cube is coming from in

your very last statement:

**igloo** **myrtilles** **fourmis**

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**ZHero****Real Member**- Registered: 2008-06-08
- Posts: 1,889

That's

If two or more thoughts intersect, there has to be a point!

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**Identity****Member**- Registered: 2007-04-18
- Posts: 934

Can't wait till I learn complex numbers, it looks so useful

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