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Does anyone know how to solve these types of problems?
logx+log(x+6)=2
I am completely lost.
Thanks _ Bob
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The two logs on the left can be combined into log(x(x+6)).
Then make both sides a power of 10 to get x(x+6) = 100, and solve the quadratic equation.
(I'm assuming both the logs are in base 10. If they're not it's still solvable, the method will just be a bit different.)
Why did the vector cross the road?
It wanted to be normal.
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Thank you I understand that part but when I do that and apply the Quadratic formula, I do not get anywhere near the answer my textbook has. There answer is X= 7.440307.
Here is my work:
x(x+6)=100
x^2+6x-100=0
a=1 b=6 c=-100
-6+or- sqr 6^2-4(1)(-100)/2=20.38
Do you know where I have gone wrong
ty
Bob
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Thank you I understand that part but when I do that and apply the Quadratic formula, I do not get anywhere near the answer my textbook has. There answer is X= 7.440307.
Here is my work:
x(x+6)=100
x^2+6x-100=0a=1 b=6 c=-100
-6+or- sqr 6^2-4(1)(-100)/2=20.38
Do you know where I have gone wrong
tyBob
You've just typed it in your calculator incorrectly. Make sure you get your order of operations right:
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